Answer:
A tree with a height of 6.2 ft is 3 standard deviations above the mean
Step-by-step explanation:
⇒ 
statement: A tree with a height of 5.4 ft is 1 standard deviation below the mean(FALSE)
an X value is found Z standard deviations from the mean mu if:
In this case we have: 
We have four different values of X and we must calculate the Z-score for each
For X =5.4\ ft
Therefore, A tree with a height of 5.4 ft is 1 standard deviation above the mean.
⇒
statement:A tree with a height of 4.6 ft is 1 standard deviation above the mean.
(FALSE)
For X =4.6 ft
Therefore, a tree with a height of 4.6 ft is 1 standard deviation below the mean
.
⇒
statement:A tree with a height of 5.8 ft is 2.5 standard deviations above the mean
(FALSE)
For X =5.8 ft
Therefore, a tree with a height of 5.8 ft is 2 standard deviation above the mean.
⇒
statement:A tree with a height of 6.2 ft is 3 standard deviations above the mean.
(TRUE)
For X =6.2\ ft
Therefore, a tree with a height of 6.2 ft is 3 standard deviations above the mean.
B. 46 feet because 132/12=11 and 12+12+11+11=46
Step-by-step explanation:
yah kaun se language mein likha hai aapane
Answer: 4x^2−4x+1
Step-by-step explanation:
(2x-1)^2
Square of Difference: (a−b)^2=a^2−2ab+b^2.
(2x)^2−2*2x+1
Multiplication Distributive Property: (xy)^a=
2^2x^2−2*2x+1
4x^2−2*2x+1
4x^2−4x+1
Hope this helps, now you know the answer and how to do it. HAVE A BLESSED AND WONDERFUL DAY! As well as a great Valentines Day! :-)
- Cutiepatutie ☺❀❤
