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Serggg [28]
3 years ago
9

Example 19 A Shop Has Six Calculators Of Which Two Are Defective. The Calculators Are Tested One After Another Until The Two Def

ective Calculators Are Discovered. (a) Copy And Complete Thr Tree Diagram To Represent This Information. (b) Calculate The Probability That The Process Will Stop On The Third Test.
Mathematics
1 answer:
erma4kov [3.2K]3 years ago
7 0
I know two ways that we can use in this problem, it depends on your knowledge in your math class.
The first way is using the combinatorial formula, and probability:
P = possibles outcomes from the event/ all outcomes from the experiment
Using combinatoria P = (2C2*4C1)/(6C3)
2C2 is the possibles ways to get two defectives and we calculate that:
2C2=2!/(2!*(2-2)!)=1
Then, 4C1 is the possibles ways to get 1 no defective (remember you need only 3 test and you expect 2 are defective from the question), calculating:
4C1=4!/(1!*(4-1)!)=4
And 6C3 represents the all possible ways to get 3 calculators (no matter if they defective or not), calculating:
6C3=6!/(3!*(6-3)!)=20
Apply p formula:
<span>P = (1*4)/20 = 1/5 = 0.2</span> in percertage 20%

The another way to calculate this problem is using the tree diagram or multiplication rule:
P=(2/6)*(1/5)*(4/4)=1/15  (here you are saying the order of computer, first and second defective and the last one no defective)
P=(2/6)*(4/5)*(1/4)=1/15 ( the second is no defective, and the others are defective)
P=(4/6)*(2/5)*(1/4)=1/15 (the first one is no defective and the others are defective)
Finally add the three result above, and get the answer:
<span>P=1/15+1/15+1/15 = 3/15 = 1/5 = </span>0.2
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4 0
3 years ago
I’m really stuck<br> Can. Someone help?
const2013 [10]

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-2\leq x < 8

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Notice that the leftmost endpoint, 2, has a closed circle, which means that it is included in the inequality. Also, the rightmost endpoint, 8, has an open circle, which means that is NOT included in the inequality.

Because the inequality only includes what is between the two numbers, you write the inequality as -2\leq x < 8 to show that -2 is included and 8 is not included.

8 0
2 years ago
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svetoff [14.1K]

You only flip the inequality sign when you multiply or divide both sides by a negative number.

================================================

Problem 1

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The inequality sign flip happens because we divided both sides by -8.

The graph will have a closed circle at 4 with shading to the left.

Three solutions are x = 0, x = 1, x = 2. You can pick any three numbers you want as long as they are 4 or smaller.

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Problem 2

1x+2x-7 < 6\\\\3x-7 < 6\\\\3x < 6+7\\\\3x < 13\\\\x < \frac{13}{3}\\\\x < 4 \frac{1}{3}

The graph will have an open circle at 13/3 = 4&1/3 = 4.333 approx. The shading is to the left. No inequality sign flip happens because we divided both sides by a positive number.

Your choice of three solutions is correct. You can pick anything smaller than 4.3333

================================================

Problem 3

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