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Serggg [28]
3 years ago
9

Example 19 A Shop Has Six Calculators Of Which Two Are Defective. The Calculators Are Tested One After Another Until The Two Def

ective Calculators Are Discovered. (a) Copy And Complete Thr Tree Diagram To Represent This Information. (b) Calculate The Probability That The Process Will Stop On The Third Test.
Mathematics
1 answer:
erma4kov [3.2K]3 years ago
7 0
I know two ways that we can use in this problem, it depends on your knowledge in your math class.
The first way is using the combinatorial formula, and probability:
P = possibles outcomes from the event/ all outcomes from the experiment
Using combinatoria P = (2C2*4C1)/(6C3)
2C2 is the possibles ways to get two defectives and we calculate that:
2C2=2!/(2!*(2-2)!)=1
Then, 4C1 is the possibles ways to get 1 no defective (remember you need only 3 test and you expect 2 are defective from the question), calculating:
4C1=4!/(1!*(4-1)!)=4
And 6C3 represents the all possible ways to get 3 calculators (no matter if they defective or not), calculating:
6C3=6!/(3!*(6-3)!)=20
Apply p formula:
<span>P = (1*4)/20 = 1/5 = 0.2</span> in percertage 20%

The another way to calculate this problem is using the tree diagram or multiplication rule:
P=(2/6)*(1/5)*(4/4)=1/15  (here you are saying the order of computer, first and second defective and the last one no defective)
P=(2/6)*(4/5)*(1/4)=1/15 ( the second is no defective, and the others are defective)
P=(4/6)*(2/5)*(1/4)=1/15 (the first one is no defective and the others are defective)
Finally add the three result above, and get the answer:
<span>P=1/15+1/15+1/15 = 3/15 = 1/5 = </span>0.2
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(8b^2/3*9t^3/5)(8b^5/3*9t^3/5)
erma4kov [3.2K]

Answer:

5,184•b•t^6/5

Step-by-step explanation:

Here, we want to multiply the expressions

According to indices law, if we have same bases, we add up the exponents

Thus, we have that;

8 *8b^(2/3+5/3) * 9 * 9 * t^(3/5+3/5)

= 64 * b * 81 * t^6/5

= 5,184bt^6/5

8 0
2 years ago
8. Find the measure of the indicated angle. Round to the nearest
Yuri [45]

Answer:

relationship between base and hypotenuse is given by cos angle

let angle be ø

cos ø=b/h

cosø=28/34

ø=cos-¹(28/34)=34.5°

5 0
3 years ago
Find the missing side lengths. Leave your answer as radicals in simplest form.
Ronch [10]

Answer:

Hence x = y = 2

Step-by-step explanation:

Using the SOH CAH TOA identity

Hypotenuse = 2√2

Opposite = x

theta = 45

Sin theta = opp/hyp

Sin 45 =x/2√2

1/√2 = x/2√2

x = 2√2 * 1/√2

x = 2

To get y we will use the pythagoras theorem;

(2√2)² = x² +y²

(2√2)² = 2²+y²

8 = 4 + y²

y² = 8-4

y² = 4

y = √4

y = 2

Hence x = y = 2

7 0
3 years ago
HELP W PROBLEM PLS !!!
bagirrra123 [75]

Answer:

sorry that hard a only in 5th grade

3 0
3 years ago
Read 2 more answers
(Q7) Determine the graph of the polar equation r = 12/6+4 cos theta.
masya89 [10]
ANSWER

b.

EXPLANATION

The given polar equation is,

r = \frac{12}{6 + 4 \cos( \theta) }

Cross multiply to get,

r(6 + 4 \cos( \theta) ) = 12

6r + 4r\cos( \theta) ) = 12

Substitute,

r\cos( \theta) = x

and

r = \sqrt{ {x}^{2} + {y}^{2} }

6 \sqrt{ {x}^{2} + {y}^{2} } + 4x = 12

3\sqrt{ {x}^{2} + {y}^{2} } + 2x = 6

3\sqrt{ {x}^{2} + {y}^{2} } = 4 - 2x

9({x}^{2} + {y}^{2}) =( 4 - 2x ) ^{2}

9{x}^{2} + 9 {y}^{2} =16 - 16x + 4x ^{2}

5{x}^{2} + 9 {y}^{2} + 16x = 16

This is an ellipse whose center is shifted to the left with orientation on the x-axis

The correct choice is B.

8 0
3 years ago
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