Use the elimination method to solve the system of equations choose the correct order pair.

Mathematics

2 answers:

ivann1987 [24]3 years ago

8 0

Answer:

Its the third choice:

(2, 5).

Step-by-step explanation:

6x + 4y = 32

-6x + 4y = 8 Adding the 2 equations:

0 + 8y = 40

8y = 40

y = 5

Now substitute for y in the first equation:

6x + 4(5) = 32

6x = 32 - 20 = 12

x = 2.

vredina [299]3 years ago

5 0

Add equation 1 and 2 to remove 6x. You will end up with
$8y = 40$
By solving, y=5

Sub 5 into any equation
$6x + 4(5) = 32$
By solving, x=2
The ordered pair is (2,5)

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Oduvanchick [21]

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Step-by-step explanation:

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3 years ago

Read 2 more answers

Find the following integral

ololo11 [35]

There's nothing preventing us from computing one integral at a time:

$\displaystyle \int_0^{2-x} xyz \,\mathrm dz = \frac12xyz^2\bigg|_{z=0}^{z=2-x} \\\\ = \frac12xy(2-x)^2$

$\displaystyle \int_0^{1-x}\int_0^{2-x}xyz\,\mathrm dz\,\mathrm dy = \frac12\int_0^{1-x}xy(2-x)^2\,\mathrm dy \\\\ = \frac14xy^2(2-x)^2\bigg|_{y=0}^{y=1-x} \\\\= \frac14x(1-x)^2(2-x)^2$

$\displaystyle\int_0^1\int_0^{1-x}\int_0^{2-x}xyz\,\mathrm dz\,\mathrm dy\,\mathrm dx = \frac14\int_0^1x(1-x)^2(2-x)^2\,\mathrm dx$

Expand the integrand completely:

$x(1-x)^2(2-x)^2 = x^5-6x^4+13x^3-12x^2+4x$

Then

$\displaystyle\frac14\int_0^1x(1-x)^2(2-x)^2\,\mathrm dx = \left(\frac16x^6-\frac65x^5+\frac{13}4x^4-4x^3+2x^2\right)\bigg|_{x=0}^{x=1} \\\\ = \boxed{\frac{13}{240}}$