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nadezda [96]
4 years ago
11

HELP! ASAP!

Physics
1 answer:
maks197457 [2]4 years ago
8 0
Hey there!
Alright, it looks like you've got the second question on the top right, but I can't figure out the answer you've got for the first.
Using Newton's Second Law Of Motion, we have:
F = ma
We plug in our values:
F = 5(1)
That would give us 5 Newtons of force.
For the last one:
Even if two balls are given the same acceleration, the determining factor is <em>weight.</em> If a ball is lighter, it needs less acceleration to go faster. If it's larger, it needs more to make it go at that same speed. That's why that 5 newtons makes sense because it's 5 kilograms as opposed to 0.6 kilograms. It's heavier, and needs more force.
Hope this helped!
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A 2190 kg car moving east at 10.5 m/s collides with a 3220 kg car moving east. The cars stick together and move east as a unit a
Bezzdna [24]

To solve this problem it is necessary to apply the concepts related to the conservation of the Momentum describing the inelastic collision of two bodies. By definition the collision between the two bodies is given as:

m_1v_1+m_2v_2 = (m_1+m_2)V_f

Where,

m_{1,2}= Mass of each object

v_{1,2}= Initial Velocity of Each object

V_f= Final Velocity

Our values are given as

m_1 = 2190Kg

v_1 =10.5m/s

m_2 = 3220kg

V_f = 4.74m/s

Replacing we have that

m_1v_1+m_2v_2 = (m_1+m_2)V_f

(2190)(10.5)+(3220)v_2 = (2190+3220)(4.74)

v_2 = 0.8224m/s

Therefore the the velocity of the 3220 kg car before the collision was 0.8224m/s

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