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Zarrin [17]
3 years ago
11

A sled whose total mass with cargo is 30.0 kg rests on ice. The coefficient of static friction is 0.20 and the coefficient of ki

netic friction is 0.15 the sled is attached to a rope horizontally in which the tension force is slowly increased how much tension force applied by the rope will cause the sled to start moving?
A. 0 N
B. 9.8 N
C. 59 N
D. 290 N
Physics
1 answer:
romanna [79]3 years ago
5 0

when sled just start to move the force on the sled will be equal to the static friction

So here we need to find the value of static friction

We know that

m = 30 kg

\mu_s = 0.20

now we know that normal force on the block is counterbalanced by weight of the block

F_n = mg

F_n = 30*9.8

now in order to find the friction force we can use

F_s = \mu_s * F_n

F_s = 0.20 * 30 * 9.8

F_s = 59 N

so it requires 59 N of force to move the sled

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xz_007 [3.2K]

Answer:

Magnitude of Vector = 79.3

Explanation:

When a vector is resolved into its rectangular components, it forms two vector components. These components  are named as x-component and y-component, they are calculated by the following formulae:

x-component of vector = (Magnitude of Vector)(Cos θ)

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where,

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Therefore, using the values in the equation of y-component, we get:

36 = (Magnitude of Vector)(Sin 27°)

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Answer:

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Explanation:

Hope it helps!!!

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which statement below is FALSE? A Gravity acts on any object with mass. B The closer objects are, the stronger the gravitational
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Explanation:

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The waves will increase in frequency since there will be more number of back and forth motions in every second.

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