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STALIN [3.7K]
11 months ago
5

How high would a projectile go if it was launched from ground level with an initial speed of 26 m/s at an angle of 30 degrees ab

ove the horizontal?
Physics
1 answer:
tigry1 [53]11 months ago
4 0

Answer:

Vy = 26 m/s sin 30 = 13 m/s      vertical speed

t = Vy / a = 13 m/s / 9.80 m/s^2 = 1.33 sec     time to reach Vy = 0

H = Vy t + 1/2 g t^2

H = 13 m/s * 1.33 sec - 1.33^2 * 9.8 / 2 m = 8.62 m

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A karate master wants to break a board by hitting the board swiftly with his hand. The master's hand has a mass of 0.30 kg, and
slava [35]

Answer:

f=-1380N

Explanation:

A karate master wants to break a board by hitting the board swiftly with his hand. The master's hand has a mass of 0.30 kg, and as it strikes the board, his hand has a velocity of 23.3 m/s. The master contacts the board for 0.0050 seconds

.the concluding part to the question should be

What is the impact force (impulse) on the board?

solution

from the Newton's second law of motion which states that

the rate of change in momentum is directly proportional to the force applied

f=m(v-u)/t

f=0.3(0-23.3)/0.005

f=-1380N

f=force impact

m=mass of the karates master's hand

t=time for the impact

v=0m/s final velocity

u=initial velocity

6 0
3 years ago
Please help i’m running out of time to answer
kipiarov [429]

Answer:

5,970 N

Explanation:

m = 597 kg

a = 10 m/s^2

Plug those values into the following equation:

F = ma

F = (597 kg)(10 m/s^2)

F = 5,970 N

4 0
3 years ago
Why is kinetic friction less than static?
alekssr [168]
The kinetic friction is usually not greater than the applied force. Keep applying more force until you reach a maximum value for the static friction
7 0
3 years ago
For an object in uniform circular motion, what can you say about the directions of the velocity, acceleration, and net force vec
tigry1 [53]

Answer: The velocity vector is perpendicular to the acceleration vector; the acceleration vector is parallel to the net force vector.

Explanation:

In a uniform circular motion, the meaning of "uniform"is the same as for an uniform straight motion, i.e., the module of the velocity vector (its speed) is constant.

Now, if the object were not describing a circular trajectory, it should move at constant speed, in a straight line, provided no external forces acted upon it.

If there is an external force acting on it, making it to follow a circular trajectory, this force doesn't change the instantaneous value of the velocity, but it changes his direction instead.

While the direction is changing, it always keep tangential to the trajectory, due to if at any moment the force disappears, the body must continue in a straight line at constant speed, following a line tangent to the circle.

It can be showed, that the acceleration vector, defined as the change in velocity over time, always aims towards the center of the circle, and is perpendicular to the velocity vector.

As the only net force acting on the object (assuming a horizontal trajectory), is the one that causes the acceleration, the acceleration vector has the same direction as the net force.

7 0
3 years ago
A truck weighing 3.0 × 104
andreev551 [17]

Answer:

A truck weighing 3.0 × 104

newtons was driven up a

hill that is 1.6 × 103

meters long to a level area that

is 8.0 × 102

meters above the starting point. If the

trip took 480 seconds, what was the minimum power

required?

Explanation:

the answer is 1292.8

<u><em>brainliest plzzzzzzzzzzzzzzzzzzzzzz</em></u>

5 0
3 years ago
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