You betcha !
-- Work is done whenever a force acts through a distance.
-- The skydiver has weight. That's the force acting on him.
-- As time goes on, I'm assuming that he falls from one height
to a lower height. That's the distance the force acts through.
-- The work done on him is (force) times (distance)
(his weight) x (distance he falls).
So where is the machine that does all this work ?
-- It's GRAVITY that does the work on him as he falls.
So how did he get all this energy in the first place ?
Where did it come from ?
-- From the airplane that lifted him up to height from which he jumped !
My calculator is about 1cm thick, 7cm wide, and 13cm long.
Its volume is (length) (width) (thick) = (13 x 7 x 1) = 91 cm³ .
The question wants me to assume that the density of my calculator
is about the same as the density of water. That doesn't seem right
to me. I could check it easily. All I have to do is put my calculator
into water, watch to see if sinks or floats, and how enthusiastically.
I won't do that. I'll accept the assumption.
If its density is actually 1 g/cm³, then its mass is about 91 grams.
The choices of answers confused me at first, until I realized that
the choices are actually 1g, 10² g, 10⁴ g, and 10⁶ g.
My result of 91 grams is about 100 grams ... about 10² grams.
Your results could be different.
If a problem says the acceleration is some positive value than solve using that value, a negative acceleration is said to be deceleration. E.g. a car decelerating at 10 m/sec can be said to be accelerating at -10 m/sec.
If a problem states decelerates at A, then use -A for acceleration in the classic equations which are for acceleration. If a problem says accelerates at a negative value like -A the use -A as the value for acceleration, it can also be said to be decelerating at A.
Answer:
Explanation:
Round to three significant digits
