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HACTEHA [7]
3 years ago
11

There will be a circular patio with a diameter of 7 metres.   greg is going to put a tiled edge around the patio. what is the ci

rcumference of the patio? m circumference of a circle = 2πr use π = 3.14
Mathematics
2 answers:
Paladinen [302]3 years ago
6 0
If diameter is7, the radius is 3.5m
so c=2πr
       =2×3.14×3.5
       =21.98m
KIM [24]3 years ago
4 0

Answer:  The circumference of the patio is 21.98 meters.

Step-by-step explanation:  Given that there is a circular patio with a diameter of 7 meters. Greg is going to put a titled edge around the patio.

We are to find the circumference of the patio.

If 'r' units is the radius of a circle, then the circumference of the circle is given by

C=2\pi r.

Since the diameter of the circular patio is 7 meters, so the radius 'r' will be given by

\textup{radius}=\dfrac{1}{2}\textup{ of the diameter}\\\\\Rightarrow r=\dfrac{1}{2}\times 7\\\\\Rightarrow r=3.5~\textup{meters.}

Therefore, the circumference of the patio is given by

C=2\pi r=2\times 3.14\times 3.5=21.98~\textup{meters}.

Thus, the circumference of the patio is 21.98 meters.

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The Paralyzed Veterans of America is a philanthropic organization that relies on contributions. They send free mailing labels an
lions [1.4K]

Answer:

Confidence interval:  (0.04649,0.04913)

Step-by-step explanation:

We are given the following in the question:

Sample size, n =  100,000

Number of people who donated, x = 4781

\hat{p} = \dfrac{x}{n} = \dfrac{4781}{100000} = 0.04781


95% Confidence interval:

\hat{p}\pm z_{stat}\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}

z_{critical}\text{ at}~\alpha_{0.05} = 1.96

Putting the values, we get:

0.04781
\pm 1.96(\sqrt{\dfrac{0.04781
(1-0.04781
)}{100000}})\\\\=0.04781
\pm 0.00132\\\\=(0.04649,0.04913)

is the required 95% confidence interval  for the true proportion of their entire mailing list who may donate.

3 0
3 years ago
Christian’s Gym charges a one-time fee of $50 plus $30 per session for a personal trainer.
nydimaria [60]

Answer: For 10 sessions, the cost of the two plans the same.

Step-by-step explanation:

Let x= Number of sessions.

Given: Christian’s Gym charges a one-time fee of $50 plus $30 per session for a personal trainer.

Total charge for x sessions = 50+30x

Nicole's fitness center charges a yearly fee of $250 plus $10 for each session with a  trainer.

Total charge for x sessions = 250+10x

When both plan charges the same, then

50+30x=250+10x\\\\\Rightarrow\ 30x-10x=250-50\\\\\Rightarrow\ 20x=200\\\\\Rightarrow\ x=10

i.e. For 10 sessions, the cost of the two plans the same.

3 0
3 years ago
Help please :) I'd greatly appreciate it
azamat
= 4i (2i) <span>√6
= 8i^2 </span><span>√6 but i^2 = -1
= - 8</span><span>√6</span><span>

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6 0
3 years ago
Jamie is selling tickets at a whale watch at a local beach.The tickets cost $24.40 for an adult and $14.50 for a child.Jamie ear
wariber [46]
30% = .3

.3(24.40a + 14.50c)

24.40 = cost of adult ticket
14.50 = cost of child ticket
a = # of adult tickets sold
c = # of child tickets sold

.3 * 24.40a + .3 * 14.50c
answer: 7.32a + 4.35c 

7 0
3 years ago
PLS ANSWER ASAP 30 POINTS!!! CHECK PHOTO! WILL MARK BRAINLIEST TO WHO ANSWERS
Sveta_85 [38]

I'll do Problem 8 to get you started

a = 4 and c = 7 are the two given sides

Use these values in the pythagorean theorem to find side b

a^2 + b^2 = c^2\\\\4^2 + b^2 = 7^2\\\\16 + b^2 = 49\\\\b^2 = 49 - 16\\\\b^2 = 33\\\\b = \sqrt{33}\\\\

With respect to reference angle A, we have:

  • opposite side = a = 4
  • adjacent side = b = \sqrt{33}
  • hypotenuse = c = 7

Now let's compute the 6 trig ratios for the angle A.

We'll start with the sine ratio which is opposite over hypotenuse.

\sin(\text{angle}) = \frac{\text{opposite}}{\text{hypotenuse}}\\\\\sin(A) = \frac{a}{c}\\\\\sin(A) = \frac{4}{7}\\\\

Then cosine which is adjacent over hypotenuse

\cos(\text{angle}) = \frac{\text{adjacent}}{\text{hypotenuse}}\\\\\cos(A) = \frac{b}{c}\\\\\cos(A) = \frac{\sqrt{33}}{7}\\\\

Tangent is the ratio of opposite over adjacent

\tan(\text{angle}) = \frac{\text{opposite}}{\text{adjacent}}\\\\\tan(A) = \frac{a}{b}\\\\\tan(A) = \frac{4}{\sqrt{33}}\\\\\tan(A) = \frac{4\sqrt{33}}{\sqrt{33}*\sqrt{33}}\\\\\tan(A) = \frac{4\sqrt{33}}{(\sqrt{33})^2}\\\\\tan(A) = \frac{4\sqrt{33}}{33}\\\\

Rationalizing the denominator may be optional, so I would ask your teacher for clarification.

So far we've taken care of 3 trig functions. The remaining 3 are reciprocals of the ones mentioned so far.

  • cosecant, abbreviated as csc, is the reciprocal of sine
  • secant, abbreviated as sec, is the reciprocal of cosine
  • cotangent, abbreviated as cot, is the reciprocal of tangent

So we'll flip the fraction of each like so:

\csc(\text{angle}) = \frac{\text{hypotenuse}}{\text{opposite}} \ \text{ ... reciprocal of sine}\\\\\csc(A) = \frac{c}{a}\\\\\csc(A) = \frac{7}{4}\\\\\sec(\text{angle}) = \frac{\text{hypotenuse}}{\text{adjacent}} \ \text{ ... reciprocal of cosine}\\\\\sec(A) = \frac{c}{b}\\\\\sec(A) = \frac{7}{\sqrt{33}} = \frac{7\sqrt{33}}{33}\\\\\cot(\text{angle}) = \frac{\text{adjacent}}{\text{opposite}} \ \text{  ... reciprocal of tangent}\\\\\cot(A) = \frac{b}{a}\\\\\cot(A) = \frac{\sqrt{33}}{4}\\\\

------------------------------------------------------

Summary:

The missing side is b = \sqrt{33}

The 6 trig functions have these results

\sin(A) = \frac{4}{7}\\\\\cos(A) = \frac{\sqrt{33}}{7}\\\\\tan(A) = \frac{4}{\sqrt{33}} = \frac{4\sqrt{33}}{33}\\\\\csc(A) = \frac{7}{4}\\\\\sec(A) = \frac{7}{\sqrt{33}} = \frac{7\sqrt{33}}{33}\\\\\cot(A) = \frac{\sqrt{33}}{4}\\\\

Rationalizing the denominator may be optional, but I would ask your teacher to be sure.

7 0
1 year ago
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