Use the table of systolic blood pressures (in mm Hg) in each arm

Mathematics

1 answer:

e-lub [12.9K]2 years ago

3 0

Answer:

The 90% confidence interval would be given by (63.330;81.070)

Step-by-step explanation:

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Let put some notation

x=left arm , y = right arm

x: 175 169 182 146 144

y: 102 101 94 79 79

Since the Confidence is 0.90 or 90%, the value of a = 0.1 and a/2= 0.05we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.05,4)".And we see that ta/2= 2.13

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Which expression is not equivalent to the other three?

Kitty [74]

The right answer is B.

The first step to answering this question is combining all like terms.

A. 2x + 2 + 2x + 3x - 8
The like terms in this expression are the x terms and the constants
So, what you would do is combine all of the x terms and combine all of the constants

(2x + 2x +3x) + (2 - 8)
7x - 6

B. 4 + 7x - 2
In this expression, you would combine all of the constants

7x + (4 - 2)
7x + 2

C. -2 + 5x + 2x - 4
For this expression, you would again, combine all of the x terms and all of the constants.

-2 + 5x + 2x - 4
(5x + 2x) + (-2 - 4)
7x - 6

D. 8x - x - 6
For this expression, you would combine all of the x terms

8x - x - 6
(8x - x) - 6
7x - 6

Now let's look at all of the new answer choices:
A. 7x - 6
B. 7x + 2
C. 7x - 6
D. 7x - 6

The question is asking you to find the one expression that's different. The only different one is B, so that's the answer.

7 0

3 years ago

Read 2 more answers

A major cab company in Chicago has computed its mean fare from O'Hare Airport to the Drake Hotel to be $28.75 , with a standard

bulgar [2K]

Answer:

Following are the solution to the given choices:

Step-by-step explanation:

Using chebyshev's theorem :

$\to P(|(x-\mu)|\leq k \sigma)\geq 1- \frac{1}{k^2}\\\\here \\ \to \mu=28.75\\\\ \to \sigma=4.44$

In point a)

$\to |(x-\mu)|= |20.17-28.75|=8.58 and \sigma=4.44 \\\\so, \\k= \frac{ |(x-\mu)| }{\sigma}$

$= \frac{8.58}{4.44} \\\\ =1.9 \\\\ =2$

$value= (1- \frac{1}{k^2}) \times 100 \% =75\%$

In point b)

$\to (1- \frac{1}{k^2}) \times 100 \% =84\% \\\\\to (1- \frac{1}{k^2})=0.84 \\\\\to \frac{1}{k^2} =0.16 \\\\\to \frac{1}{k}=0.4\\\\ \to k=2.5 \\\\\to |(x-\mu)| \leq k \sigma \\\\= |(x-\mu)|\leq 2.5 \times 4.44 \\\\ = |(x-\mu)|\leq 1.11 \\\\ = (28.75\pm 11.1) \\\\\to \text{fares lies between}(17.65,39.85)$

In point c)

$\to 99.7 \% \\ lie \ between=28.75 \pm z(.03)\times \sigma \\\\ =28.75\pm 2.97 \times 4.44\\\\=(28.75\pm 13.1)\\\\=(15.65,41.85)\\$

In point d)

using standard normal variate

$x=20.17\\\\ z=-2 \\\\x=37.13\\\\ z=2\\\\\to P(20.17$

8 0

2 years ago

If your current examination mean is 97.2 and you receive a 99 on the next examination, what effect will this have?

mr Goodwill [35]

If you have an average of 97.2 on your current exam and you get a 99 on your next exam, your average will increase.

Mean in mathematics is the sum (total) of all the values in a set of data, such as numbers or measurements, divided by the total number of values.