Answer:
g(x) -x+9
Step-by-step explanation:
It is g(x) -x+9 because when you are reflecting along the y axis, you are something focusing on making the x negative(by multiplying by -1)
Answer:
The second time when Luiza reaches a height of 1.2 m = 2 08 s
Step-by-step explanation:
Complete Question
Luiza is jumping on a trampoline. Ht models her distance above the ground (in m) t seconds after she starts jumping. Here, the angle is entered in radians.
H(t) = -0.6 cos (2pi/2.5)t + 1.5.
What is the second time when Luiza reaches a height of 1.2 m? Round your final answer to the nearest hundredth of a second.
Solution
Luiza is jumping on trampolines and her height above the levelled ground at any time, t, is given as
H(t) = -0.6cos(2π/2.5)t + 1.5
What is t when H = 1.2 m
1.2 = -0.6cos(2π/2.5)t + 1.5
0.6cos(2π/2.5)t = 1.2 - 1.5 = -0.3
Cos (2π/2.5)t = (0.3/0.6) = 0.5
Note that in radians,
Cos (π/3) = 0.5
This is the first time, the second time that cos θ = 0.5 is in the fourth quadrant,
Cos (5π/3) = 0.5
So,
Cos (2π/2.5)t = Cos (5π/3)
(2π/2.5)t = (5π/3)
(2/2.5) × t = (5/3)
t = (5/3) × (2.5/2) = 2.0833333 = 2.08 s to the neareast hundredth of a second.
Hope this Helps!!!
Answer:
1232
Step-by-step explanation:
1232 6th grades went on the trip because 160p multiplied by .77, the amount of chaired covered by 6th graders, is equal to 1232.
Answer: A pure mathematics internet could be a 2-dimensional form that may be rolled-up to make a three-d form or a solid. Or a internet could be a pattern created once the surface of a solid figure is ordered out flat showing every face of the figure. A solid could have totally different nets.
Step-by-step explanation: A pure mathematics web could be a 2-dimensional form which will be closed to make a third-dimensional form or a solid. Or a web could be a pattern created once the surface of a solid figure is arranged out flat showing every face of the figure. A solid could have completely different nets.
Answer:
umm you have to give us more info
Step-by-step explanation:
without info we can not properly answer the question
