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romanna [79]
4 years ago
8

Which function has a domain of all real numbers except x=π/2 ±nπ?

Mathematics
1 answer:
boyakko [2]4 years ago
4 0
<span>A. y=secx This problem deals with the various trig functions and is looking for those points where they are undefined. Since the only math operations involved is division, that will happen with the associated trig function attempts to divide by zero. So let's look at the functions that are a composite of sin and cos. sin and cos are defined for all real numbers and range in value from -1 to 1. sin is zero for all integral multiples of pi, and cos is zero for all integral multiples of pi plus pi over 2. So the functions that are undefined will be those that divide by cos. tan = sin/cos, which will be undefined for x = π/2 ±nπ cot = cos/sin, which will be undefined for x = ±nπ sec = 1/cos, which will be undefined for x = π/2 ±nπ csc = 1/sin, which will be undefined for x = ±nπ Now let's look at the options and pick the correct one. A. y=secx * There's a division by cos, so this is the correct choice. B. y=cosx * cos is defined over the entire domain, so this is a bad choice. C. y=1/sinx * The division is by sin, not cos. So this is a bad choice. D. y=cotx, * The division is by sin, not cos. So this is a bad choice.</span>
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Therefore there are infinitely many solution to the given set of equations.
6 0
3 years ago
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finlep [7]

Answer:

A'(6, 6)

B'(7, 2)

C'(5, 1)

Step-by-step explanation:

IK

5 0
3 years ago
PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!! I CANNOT RETAKE THIS!!
liberstina [14]

Answer: C) x = 3, (x = 2 is an extraneous solution)

<u>Step-by-step explanation:</u>

\frac{x}{x-1} - \frac{1}{x-2} = \frac{2x-5}{x^{2}-3x+2}

\frac{x}{x-1} - \frac{1}{x-2} = \frac{2x-5}{(x-1)(x-2)}

Restrictions: <em>Denominator cannot equal zero</em> (x - 1 ≠ 0) and (x - 2 ≠ 0), so x ≠ 1 and x ≠ 2

(x - 1)(x - 2)\frac{x}{x-1} - (x - 1)(x - 2)\frac{1}{x-2} = (x - 1)(x - 2)\frac{2x-5}{(x-1)(x-2)}

x(x - 2) - 1(x - 1) = 2x - 5

x² - 2x - x + 1 = 2x - 5

x² - 3x + 1 = 2x - 5

<u>     -2x + 5</u>  <u>-2x + 5 </u>

x² - 5x + 6 = 0

(x - 2)(x - 3) = 0

x - 2 = 0     x - 3 = 0

  x = 2         x = 3

NOTE: x = 2 is an extraneous solution because it is one of the restricted values.

4 0
3 years ago
Function A is represented by the equation y = 2x+5.
Ahat [919]

Answer:

i think its A or D but idrk, it has been 3 days so what did you choose and did you get it right or wrong?

Step-by-step explanation:

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3 years ago
I’m confused!
denis-greek [22]

Answer:

I have found unreliable people would leave message and fail to answer properly and not always report but then found their answer was deleted later- but sometimes its straight away as repeat offenders often have all of their answers deleted at once

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3 years ago
Read 2 more answers
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