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Slav-nsk [51]
3 years ago
5

hi how are you how do i get the answers for my self because i am a teacher and get just the test with out the answer on them for

the students
Mathematics
1 answer:
Daniel [21]3 years ago
4 0
Well, I saw my teacher solving the test herself, and then grading papers off of her paper that she solved. My teacher made the answer key for the tests.
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A researcher determines that students are active about 60 + 12 (M + SD) minutes per day. Assuming these data are normally distri
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Answer:

The correct option is (b).

Step-by-step explanation:

If X \sim N (µ, σ²), then Z=\frac{X-\mu}{\sigma}, is a standard normal variate with mean, E (Z) = 0 and Var (Z) = 1. That is, Z \sim N (0, 1).

The distribution of these z-variate is known as the standard normal distribution.

The mean and standard deviation of the active minutes of students is:

<em>μ</em> = 60 minutes

<em>σ </em> = 12 minutes

Compute the <em>z</em>-score for the student being active 48 minutes as follows:

Z=\frac{X-\mu}{\sigma}=\frac{48-60}{12}=\frac{-12}{12}=-1.0

Thus, the <em>z</em>-score for the student being active 48 minutes is -1.0.

The correct option is (b).

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