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4 years ago

9

In what two instances does power output become greater

1 answer:

balu736 [363]4 years ago

5 0

The two instances wherein power output becomes greater are: "<span>when more work is done in a given amount of and time when the time it takes to do a certain amount of work is decreased." In addition, power output is typically measured in horsepower, watts or foot-pounds per minute.</span>

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You kick a soccer ball of mass 0.41 kg. the ball leaves your foot with an initial speed of 23 m/s. (a what is the magnitude of t

svetoff [14.1K]

Impulse describes the change of momentum. Since we don't know the momentum of the soccer ball before the hit, this question is hard to answer. If you assume the momentum of the ball before the hit was p = 0, then the change in momentum is just Δp = Impulse = mv.

7 0

3 years ago

Read 2 more answers

An electron moves through a uniform electric field E = (2.00î + 5.40ĵ) V/m and a uniform magnetic field B = 0.400k T. Determine

EleoNora [17]

Answer: $a=1.75\times 10^{21}\left ( 2\hat{i}5.08\hat{j}\right )$

Explanation:

Given

Electric Field $\vec{E}=2\hat{i}+5.4\hat{j}$

$\vec{B}=0.4\hat{k}\ T$

velocity $\vec{v}=8\hat{i} m/s$

mass of electron $m=9.1\times 10^{-31} kg$

Force on a charge Particle moving in Magnetic Field

$F=e\left [ \vec{E}+\left ( \vec{v}\times \vec{B}\right )\right ]$

$a=\frac{e\left [ \vec{E}+\left ( \vec{v}\times \vec{B}\right )\right ]}{m}$

$a=\frac{1.6\times 10^{-19}\left [ 2\hat{i}+5.4\hat{j}+\left ( 8\hat{i}\times 0.4\hat{k}\right )\right ]}{9.1\times 10^{-31}}$

$a=1.75\times 10^{21}\left ( 2\hat{i}+5.08\hat{j}\right )\ m/s^2$

7 0

3 years ago

In the Bohr model of the hydrogen atom, an electron moves in a circular path around a proton. The speed of the electron is appro

Alexxx [7]

Explanation:

It is given that,

Radius of the circular orbit, $r=0.53\times 10^{-10}\ m$

Speed of the electron, $v=2.2\times 10^6\ m/s$

Mass of the electron, $m=9.1\times 10^{-31}\ kg$

(a) The force acting on the electron is centripetal force. Its formula is given by :

$F=\dfrac{mv^2}{r}$

$F=\dfrac{9.1\times 10^{-31}\times (2.2\times 10^6)^2}{0.53\times 10^{-10}}$

$F=8.31\times 10^{-8}\ N$

(b) The centripetal acceleration of the electron is given by :

$a=\dfrac{v^2}{r}$

$a=\dfrac{(2.2\times 10^6)^2}{0.53\times 10^{-10}}$

$a=9.13\times 10^{22}\ m/s^2$

Hence, this is the required solution.

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3 years ago

A pole that is 2.9m tall casts a shadow that is 1.32m long. at the same time, a nearby tower casts a shadow that is 37.75m long.

Mrrafil [7]

$\frac{2.9}{1.32}$ = $\frac{x}{37.75}$

x = 82.93 m

Nothing to deal with physics.
Maths. Scale factor. Year 9.

5 0

4 years ago

Two sources of light of wavelength 710 nm are 9 m away from a pinhole of diameter 1 mm. How far apart must the sources be for th

Zepler [3.9K]

Answer:

7.8 mm

Explanation:

Wavelength = λ = 710 nm = 710×10⁻⁹ m

Distance between light sources = L = 9 m

Diameter of pinhole = d = 1 mm = 1×10⁻³ m

Rayleigh Criterion

$D=1.22\frac{L\lambda}{d}\\\Rightarrow D=1.22\frac{9\times 710\times 10^{-9}}{1\times 10^{-3}}\\\Rightarrow D=0.0077\ m=7.8\ mm$

Distance between difraction pattern is 7.8 mm.

4 0

4 years ago