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3 years ago

The movement of bones around a fixed angle without lateral displacement is called

1 answer:

3 0

The answer to the question being asked on what do you called when the movement of the bones around a fixed angle without lateral displacement is ROTATION. Rotation movement allows the bone to move in a single long axis without being displaced.

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a boy is standing 4 meter from a plane mirror how far and in what distance must te move so that he will be 4 meter from his imag

Alona [7]

Answer:

2 meters towards the mirror.

Explanation:

In a plane mirror the image distance is equal to the object distance. Therefore, by moving 2 meters towards the mirror, the boy reduces the distance between him and the mirror to two meters which is the object distance. The image distance is also 2 meters. add the two distances you will get four meters.

6 0

3 years ago

The mass of a triton is

Margarita [4]

2.14x 1022 kg

the 22 is a xponet of ten

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3 years ago

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An organism lives in the darkest aquatic ecosystem, where light cannot reach. Which ecosystem is this organism most likely in?

bazaltina [42]

The deep sea vents at the very bottom of the ocean. The thermal vent communities as otherwise stated.

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3 years ago

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A 75kg Tibetan is trekking along flat, but icy ledge with his 450kg yak when he slips over the edge. Luckily, he is holding the

Tcecarenko [31]

Answer:

minimal coefficient of static friction: $\mu_s=0.1667$

Explanation:

Once the Tibetan is hanging from the strap, he is exerting a horizontal force on the yak equal to his weight which is the product of his mass times the acceleration of gravity (g) as written below:

$w = m\,*\,g= 75\,kg\,*\,g$

The other forces acting on the yak are (see attached diagram):

* the force of gravity on the yak (identified in blue color in the image as $F_g$ ,

* the normal force (indicated in green in the image and identified by the letter "n") of the ledge on the yak as reaction to the yak's weight

* the force of static friction between the yak's hooves and the ledge (pictured in red in the image and identified with $f_s$ )

Since the normal force and the force of gravity on the yak cancel each other (balance - the yak is not moving vertically), the only forces we need to analyse are the force of the Tibetan's weight via the strap, and the force of static friction which should at least be equal in magnitude so the Tibetan doesn't fall. We assume these two forces are acting horizontally (one to the right: the Tibetan's weight, and one to the left: the static friction).

As we said, we want them to be at least equal so thy are in balance.

We recall that the force of static friction is the product of the normal force (n) times the coefficient of static friction ( $\mu_s$ ), such that: $f_s=\mu_s\,*\,n$

In our case these are the forces at play:

$F_g= M\,*\,g=450\, kg \,*\,g\\n=F_g=450\,kg\,*\,g\\f_s=\mu_s\,*\,n=\mu_s\,*450\,kg\,*\,g\\w=m\,*\,g=75\,kg\,*\,g$

So we need to find what is the minimum coefficient of static friction that precludes the Tibetan from falling. We therefore proceed to make an equality between the force of static friction on the yak and the weight of the Tibetan:

$f_s=w\\\mu_s\,*450\,kg\,*g=75\,kg\,*\,g$

and proceed to solve for the coefficient of friction by dividing both sides by "g" (which by the way cancels out), and by the yak's mass:

$\mu_s\,*450\,kg\,*g=75\,kg\,*\,g\\\mu_s=\frac{75}{450} \\\mu_s=0.1667$

where we have rounded to four decimal places the periodic number that the quotient generates. Notice that as expected, the coefficient of friction has no units (they all cancelled out in the division).

5 0

3 years ago

The unique sound quality of a clarinet or a violin is caused by the a. forced vibrations that occur at natural frequencies. b. l

julia-pushkina [17]

Answer:

The unique sound quality of a clarinet or a violin is caused by the relative intensity of different harmonics in each note.

7 0

3 years ago