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Veseljchak [2.6K]
3 years ago
9

Which one of the following statements concerning momentum is true? Group of answer choices Momentum is a force. Momentum is a sc

alar quantity. The SI unit of momentum is kg *m^2/s. The momentum of an object is always positive. Momentum and impulse are measured in the same units.
Physics
1 answer:
gtnhenbr [62]3 years ago
3 0

Question:

Which one of the following statements concerning momentum is true? Group of answer choices

A.Momentum is a force.

B.Momentum is a scalar quantity.

C.The SI unit of momentum is kg *m^2/s.

D.The momentum of an object is always positive.

E.Momentum and impulse are measured in the same units.

Answer:

Correct answer is E.

Explanation:

A. Momentum is not force ,but force is rate of change of momentum , so this statement is wrong.

B. Momentum is a vector quantity , it has magnitude and direction as well.

So statement is wrong.

C. The SI unit of momentum is kg *m/s. Wrong statement.

D.Momentum of object may be negative positive or zero. So statement is correct.

E. Both momentum and impulse has unit kg *m/s. So statement is correct.

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A car accelerates from rest at 1.0 m/s2 for 20.0 second along a straight road. It then moves at a constant speed for half an hou
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Total distance = 36500 m

The average velocity = 19.73 m/s

<h3>Further explanation</h3>

Given

vo=initial velocity=0(from rest)

a=acceleration= 1 m/s²

t₁ = 20 s

t₂ = 0.5 hr = 1800 s

t₃= 30 s

Required

Total distance

Solution

State 1 : acceleration

\tt d=vo.t+\dfrac{1}{2}at^2\\\\d=\dfrac{1}{2}\times 1\times 20^2\rightarrow vo=0\\\\d=200~m

\tt vt=vo+at\\\\vt=at\rightarrow vo=0\\\\vt=1\times 20\\\\vt=20~m/s

State 2 : constant speed

\tt d=v\times t\\\\d=20\times 1800\\\\d=36000~m

State 3 : deceleration

\tt vt=vo+at\rightarrow vt=0(stop)\\\\vo=-at\\\\20=-a.30~s\\\\a=-\dfrac{2}{3}m/s^2(negative=deceleration)

\tt d=vot+\dfrac{1}{2}at^2\\\\d=20.30-\dfrac{1}{2}.\dfrac{2}{3}.30^2\\\\d=300~m

Total distance : state 1+ state 2+state 3

\tt 200 + 36000 + 300=36500~m

the average velocity = total distance : total time

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4 0
2 years ago
A cannonball is fired at a 45.0° angle and an initial velocity of 670 m/s. Assume no air resistance. What is the vertical compon
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Answer:

<h3>473.8 m/s; 473.8 m/s</h3>

Explanation:

Given the initial velocity U = 670m/s

Horizontal velocity Ux = Ucos theta

Vertical component of the cannon velocity Uy = Usin theta

Given

U = 670m/s

theta = 45°

horizontal component of the cannonball’s velocity = 670 cos 45

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horizontal component of the cannonball’s velocity = 473.757m/s

Vertical component of the cannonball’s velocity = 670 sin 45

Vertical component of the cannonball’s velocity  = 670 (0.7071)

Vertical component of the cannonball’s velocity  = 473.757m/s

Hence pair of answer is 473.8 m/s; 473.8 m/s

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