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inna [77]
4 years ago
6

Suppose that the sales at Borders bookstores went from 7878 million dollars in 19921992 to 412412 million dollars in 19971997. F

ind an exponential function to model the sales (in millions of dollars) as a function of years, tt, since 19921992.
Mathematics
1 answer:
Zepler [3.9K]4 years ago
5 0

Answer:

S(t) = 78000000*e^0.333t

Step-by-step explanation:

Given the following :

Sales in 1992 = $78 million

Sales in 1997 = $412 million

Exponential function that models the sales in millions of dollars as a function of years t since 1992.

S(t) = So*e^kt

S(t) = sales in t years ; So = Initial or starting sales

Find k :

S(t) = sales in 1997 = $412,000,000

So = sales in 1992 = $78,000,000

t = 1997 - 1992 = 5

412,000,000 = 78,000,000 × e^k5

412,000,000 = 78,000,000 × e^5k

412,000,000/ 78,000,000 = e^5k

5.2820512 = e^5k

In(5.2820512) = In(e^5k)

1.6643145 = 5k

k = 1.6643145 / 5

k = 0.3328629

k = 0.333 ( to 3 decimal places)

Hence,

S(t) = 78000000*e^0.333t

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Answer:

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Step-by-step explanation:

The start of the question doesn't matter entirely, although is interesting to read. What we are trying to do is find the value for p such that 1000p(1-p) is maximized. Once we have that p, we can easily find the answer to part b.

Finding the value that maximizes 1000p(1-p) is the same as finding the value that maximizes p(1-p), just on a smaller scale. So, we really want to maximize p(1-p). To do this, we will do a trick called completing the square.

p(1-p)=p-p^2=-p^2+p=-(p^2-p)=-(p^2-p+1/4)-(-1/4)=-(p-1/2)^2+1/4.

Because there is a negative sign in front of the big squared term, combined with the fact that a square is always positive, means we need to find the value of p such that the inner part of the square term is equal to 0.

p-1/2=0\\p=1/2.

So, the answer to part a is \boxed{1/2}.

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1000(1/2)(1-1/2)=1000(1/2)(1/2)=1000*1/4=250.

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And we're done!

3 0
3 years ago
If u need points just answer this
sasho [114]

OK im answering ............................................................................................................

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