The given plane, 
, has normal vector 
. Any plane parallel to this one has the same normal vector.
Let 
be any point in the plane we want. The plane contains the point (1, 1, -1), so an arbitrary vector in this plane is
and this is perpendicular to 
.
So the equation of the plane is
or equivalently,
Answer:
x=-1.83
Step-by-step explanation:
1-2x=4(x+3)
1-2x=4x+12
-2x=4x+12-1
-2x=4x+11
-2x-4x=11
-6x=11
x=11÷-6
x=-1.83
Answer:
x = 61
Step-by-step explanation:
Left hand triangle containing 1 angle of 74
Label the other angle opposite the marked side also as 74
Find the third angle. Call it y.
y + 74 + 74 = 180 Combine like terms
y + 148 = 180 Subtract 148 from both sides.
y = 180 - 148
y = 32
=============
Now work with the triangle on the right.
label the angle making up the right angle = z
32 + z = 90 These two angles are complementary = 90
32 - 32 + z = 90 - 32 Subtract 32 from both sides
z = 58 Use 58 wherever you see z
x + x + z = 180 Substitute
2x + 58 = 180 Subtract 58 from both sides
2x = 122 Divide by 2
x = 61
2 to the 30 power is <span>1073741824</span>
♥ Solve:
(Arjun) 40*30=1200
(Dalia) 55*30=1650
Now subtract
1650-1200=450.
That means that Dalia will type 450 minutes more.
Final answer: 450
