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Alex_Xolod [135]
4 years ago
12

» 10*9*8*7*6*5*4*3*2*1 = 10! Is it possible?

Mathematics
1 answer:
Lyrx [107]4 years ago
8 0

Answer:

иσ ιт ιѕит тнє ρяσвℓєм α¢тυαℓℓу єqυαℓѕ=3,628,800

Step-by-step explanation:

ι нσρє ι ¢συℓ∂ няℓρ уσυ συт тσ∂αу!!!!!

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Is 0.0009999 closest to 0, 1/2, or 1
Mashcka [7]
Its closest to 0 because the value is far to the right of the decimal point
7 0
4 years ago
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Please help me i need it fast
aev [14]

Answer:

20x^3/4x7

20/4x^4

5/x^4

Step-by-step explanation:

7 0
3 years ago
What is 10÷5/8 in a math order.
Sedbober [7]
If you would like to calculate <span>10÷5/8, you can do this using the following steps:

</span><span>10÷5/8 = (10/5)/8 = 2/8 = 1/4 = 0.25

The correct result would be 1/4 or 0.25.</span>
3 0
4 years ago
At noon Joyce drove to the lake at 30 miles per hour. but she made the long walk back home at 4 miles per hour. How long did she
mars1129 [50]

Answer:

60 miles

Step-by-step explanation:

let d = distance to the lake

Using:  time = distance ÷ speed

Create expressions for the time it takes for each journey:

Drive:  t_1=\dfrac{d}{30}

Walk:   t_2=\dfrac{d}{4}

If total time = 17 hours

\implies t_1+t_2=17

\implies \dfrac{d}{30}+\dfrac{d}{4}=17

\implies \dfrac{17d}{60}=17

\implies 17d=1020

\implies d=\dfrac{1020}{17}

\implies d=60

Therefore she walked 60 miles

3 0
2 years ago
Read 2 more answers
Identify the lower class​ limits, upper class​ limits, class​ width, class​ midpoints, and class boundaries for the given freque
maw [93]

Answer:

The number of individuals included in the summary is 146.

Step-by-step explanation:

The frequency distribution table provided is as follows:

Class Intervals    Frequency

    100 - 199               24

   200 - 299              90

   300 - 399              27

   400 - 499                1

   500 - 599               4

The lower class limit it the smallest value of each class interval.

Lower class limit = {100, 200, 300, 400, 500}

The upper class limit it the highest value of each class interval.

Upper class limit = {199, 299, 399, 499, 599}

The lower class boundaries are the lower class limits decreased by 0.5 and the upper class boundaries are the upper class limits increased by 0.5.

Class boundaries:

   99.5 - 199.5  

  199.5 - 299.5

  299.5 - 399.5

  399.5 - 499.5

  499.5 - 599.5

The class width is the difference between the class boundaries of each class.

Class width = 199.5 - 99.5 = 100

So, the class width is 100.

The midpoints of a class is the average value of the boundaries of a class.

\text{Midpoint}_{100-199}=\frac{\text{Lower class boundary} + \text{Upper class boundary}}{2}\\

                         =\frac{99.5+199.5}{2}\\\\=149.5

\text{Midpoint}_{200-299}=\frac{\text{Lower class boundary} + \text{Upper class boundary}}{2}\\

                         =\frac{199.5+299.5}{2}\\\\=249.5

\text{Midpoint}_{300-399}=\frac{\text{Lower class boundary} + \text{Upper class boundary}}{2}\\

                         =\frac{299.5+399.5}{2}\\\\=349.5

\text{Midpoint}_{400-499}=\frac{\text{Lower class boundary} + \text{Upper class boundary}}{2}\\

                         =\frac{399.5+499.5}{2}\\\\=449.5

\text{Midpoint}_{500-599}=\frac{\text{Lower class boundary} + \text{Upper class boundary}}{2}\\

                         =\frac{499.5+599.5}{2}\\\\=549.5

The number of individuals included in the summary is the sum of all frequencies.

\text{Number of Individuals}=24 + 90 + 27 + 1 + 4=146

Thus, the number of individuals included in the summary is 146.

3 0
3 years ago
Read 2 more answers
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