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3 years ago

Find the evalue of x and z

Mathematics

1 answer:

tensa zangetsu [6.8K]3 years ago

4 0

Uh where's problem??

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If, in a right triangle,

Reptile [31]

Elijahlouis, I will not sure how I am going on with my friends. we will need the following

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3 years ago

What is the answer to ...8.42 x 9

3241004551 [841]

Answer:

75.78

Step-by-step explanation:

8.42*9=75.78

6 0

3 years ago

Read 2 more answers

PLEASE HELP I NEED HELP

bulgar [2K]

Yes because each x value differ by 2.5 and each y value also differs at aconstant rat of 1

3 0

3 years ago

Given m ZLMN = 145°, what is m ZXMN?<br> Show all relevant work.

myrzilka [38]

80 degrees. 145 = (4x+5) + (6x-10) = 10x-5... so 10x = 150, x = 15. LMN = 6x-10 = 6(15) - 10 = 80.

4 0

4 years ago

Reptile [31]

Answer:

The real zeros of f(x) are x = 0.3 and x = -3.3.

Step-by-step explanation:

Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:

$ax^{2} + bx + c, a\neq0$ .

This polynomial has roots $x_{1}, x_{2}$ such that $ax^{2} + bx + c = a(x - x_{1})*(x - x_{2})$ , given by the following formulas:

$x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}$

$x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a}$

$\bigtriangleup = b^{2} - 4ac$

In this problem, we have that:

$f(x) = x^{2} + 3x - 1$

$a = 1, b = 3, c = -1$

$\bigtriangleup = 3^{2} - 4*1*(-1) = 13$

$x_{1} = \frac{-3 + \sqrt{13}}{2*1} = 0.3$

$x_{2} = \frac{-3 - \sqrt{13}}{2*1} = -3.3$

The real zeros of f(x) are x = 0.3 and x = -3.3.

7 0

3 years ago