Question

A cylindrical basin is 2 feet tall and has a diameter of 5 feet, as shown. If the basin is completely filled with water, how much water will it hold? Round the answer to the nearest tenth of a foot.

Answer 1

Answer:

$39.3 ft^3$

Step-by-step explanation:

The cylindrical basin has a height of 2 ft and a diameter of 5 ft.

To find the amount of water that will completely fill up the basin, we simply need to find the volume of the basin.

The volume of a cylinder is given as:

$V = \pi r^2h$

where r = radius of the basin (half the diameter) = 2.5 ft

h = height of the basin

Hence, the volume is:

$V = \pi * 2.5^2 * 2$

$V = 39.27 ft^3$ ≅ $39.3 ft^3$

The cylindrical basin can hold up to $39.3 ft^3$ of water.

Answer 2

Answer:

39.3

Step-by-step explanation:

got it right on edge