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3 years ago

Identify growth or decay then describe its rate (r=%) Y=e^-0.3t

1 answer:

7 0

Y=e^-0.3t would better be written as y<span>=e^(-0.3t), because you want to emphasize that the exponent of "e" is -0.3t. Enclose the expon. within ( ), ps.

Since the expo is neg, this is expo. decay, and the rate is 0.3 per time period.

For example, if y is = to .5 right now, the next value, after 1 time period, will be
.5(.3) = .15.</span>

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suppose it takes 48 chickens fingers to feed Mr . Youngs 4th grade class of 20 students how many chicken fingers would be needed

Mrrafil [7]

30 is 1.5 times greater than 20 so 48*1.5 = 72
it would take 72 chicken fingers to feed 30 students

6 0

3 years ago

mr ogata drove 276 mies from his house to los angeles at an average speed of 62 miles per hour. how long did it take him to get

Ilia_Sergeevich [38]

About 5 hours. I did this by dividing and rounding 276 by 62. Hope this helps!

4 0

2 years ago

Thrice the product of two and "Y".

love history [14]

Answer:

Step-by-step explanation:

We need to solve the statement ' Thrice the product of two and "Y" '.

Thrice means 3 times and product means multiply. It means we have to multiply 3,2 and Y.

Let the result is R. It can be calculated as follows :

$R=3\times 2\times Y$

We know that, 3×2 = 6

So,

$R=6Y$

Hence, Thrice the product of two and "Y" is 6Y.

6 0

3 years ago

Find the average rate of change for f(x) = x2 + 9x + 18 from x = −10 to x = 10.

igor_vitrenko [27]

The average rate of change formula is
f(b) - f(a)
arc = ----------------
b-a

Here, a= -10 and b = 10

(10)^2 + 9(10) + 18 - [ (-10)^2 + 9(-10) + 18]
Here arc = --------------------------------------------------------------
10 - (-10)

10^2 and -(-10)^2 cancel. 18 - 18 cancel.

90 - (-90) 180
This leaves us with arc = ----------------- = ------------- = 9 (answer)
20 20

7 0

3 years ago

Use l'Hôpital's Rule to find the following limit. ModifyingBelow lim With x right arrow 0StartFraction 3 sine (x )minus 3 x Ove

steposvetlana [31]

Answer:

$\lim_{x \to 0} \frac{3sinx-3x}{7x^3}=-\frac{1}{14}$

Step-by-step explanation:

The limit is:

$\lim_{x \to 0} \frac{3sinx-3x}{7x^3}=\frac{0}{0}$

so, you have an indeterminate result. By using the l'Hôpital's rule you have:

$\lim_{x \to 0} \frac{a(x)}{b(x)}= \lim_{x \to 0} \frac{a'(x)}{b'(x)}$

by replacing, and applying repeatedly you obtain:

$\lim_{x \to 0} \frac{3sinx-3x}{7x^3}= \lim_{x \to 0}\frac{3cosx-3}{21x^2}= \lim_{x \to 0}\frac{-3sinx}{42x}= \lim_{x \to 0}\frac{-3cosx}{42}\\\\ \lim_{x \to 0} \frac{3sinx-3x}{7x^3}=\frac{-3cos0}{42}=-\frac{1}{14}$

hence, the limit of the function is -1/14

8 0

3 years ago