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harina [27]
3 years ago
11

Two high school students are hired to rake leaves .

Mathematics
1 answer:
Arlecino [84]3 years ago
4 0

Answer:

okay whatever you think

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In a right triangle, the side adjacent to angle x is 4 units. The side opposite that angle is 9 units. What is the tangent ratio
puteri [66]
Answer: C
The formula for tangent is tan(x)= opposite/ adjacent so plugging it in would be tan(x)=9/4
4 0
2 years ago
Read 2 more answers
A kite flying in the air has a 12 line attached to it. Its line is pulled taut and casts a 9 shadow. Find the height of the kite
alexira [117]

Answer:

8 (7.94)

Step-by-step explanation:

You can think of it as a geometry problem.

What is formed here is a triangle, which sides ate: the line, the line's shadow, and the height from the ground to the kite (here I attach a drawing).

What you need to find is the height. We will call it H.

As the triangle formed is a right one, we can use Pitágoras' theorem. The height H squared plus the squared of the shadow is equal to the squared of the line (the hypotenuse). This is:

H^2 + 9^2 = 12^2

H^2 + 81= 144

H^2 = 63

Applying squared root in both sides

H = √63

H = 7,94

So, the height is approximately 8.

4 0
3 years ago
Which of the following is a true statement about functions?
chubhunter [2.5K]

Answer:

A

Step-by-step explanation:

6 0
3 years ago
HELP ASAP!<br><br> it's for a math quiz so thanks
satela [25.4K]
I’m 90% sure that the answer is 36x
5 0
2 years ago
If 0°&lt;0&lt;90° and sin0=12/13, find cos0 using trigonometric identities.
Aleks04 [339]

here's the solution,

we know :

\sin( \theta)  =  \dfrac{perpendicular}{hypotenuse}

So,

\dfrac{p}{h}  =  \dfrac{12}{13}

so.. let the perpendicular be 12x and hypotenuse be 13x

now,

by applying pythagoras theorem,

  • b {}^{2}  = h {}^{2}  - p {}^{2}

where,

  • b = base
  • h = hypotenuse
  • p = perpendicular

So,

  • b {}^{2}  =  ({13x})^{2}  -  ({12x})^{2}
  • b  {}^{2} = 169x {}^{2}  - 144x {}^{2}
  • {b}^{2}  = 25x {}^{2}
  • b  = 5x

so,

  • \cos( \theta)  =  \dfrac{b}{h}

  • \cos( \theta)  =   \dfrac{5x}{13x}

  • \cos( \theta)  =  \dfrac{5}{13}

hope it helps !!

3 0
3 years ago
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