Answer:
First question: LCL = 522, UCL = 1000.5
Second question: A sample size no smaller than 418 is needed.
Step-by-step explanation:
First question:
Lower bound:
0.36 of 1450. So
0.36*1450 = 522
Upper bound:
0.69 of 1450. So
0.69*1450 = 1000.5
LCL = 522, UCL = 1000.5
Second question:
In a sample with a number n of people surveyed with a probability of a success of 
, and a confidence level of 
, we have the following confidence interval of proportions.
In which
z is the zscore that has a pvalue of 
.
The margin of error is:
The project manager believes that p will turn out to be approximately 0.11.
This means that 
95% confidence level
So 
, z is the value of Z that has a pvalue of 
, so 
.
The project manager wants to estimate the proportion to within 0.03
This means that the sample size needed is given by n, and n is found when M = 0.03. So
Rounding up
A sample size no smaller than 418 is needed.
Answers are 2 and 3
supplementary angles and adjacent angles
Answer:
<u><em>4 : </em></u> Coordinate of Q = 
<em><u>5 : </u></em> Coordinate of point A = (-2,-2)
Explanation :
4) Given the points M(-3, -4) and T(5,0)
x₁= -3, y₁ = -4 and
x₂ = 5, y₂ = 0
m = 2, n = 1
Now apply the section formula,
{(mx₂+nx₁)/(m+n) , (my₂+ny₁)/(m+n)}
Coordinate of point Q =
5) AB:BC = 3:4
A = (x,y), end point
B = (4, 1)
C = (12, 5) end point
So, m = 3 & n = 4
x₁ = x , y₁ = y , x₂=12 & y₂ = 5
Apply section formula we get
4 = (36+4x)/7 & 1 = (15 + 4y)/7
28= 36 + 4x 7 = 4y + 15
4x =-8 4y =-8
x = -2 y = -2
Answer:
86°
Step-by-step explanation:
- Angles on a straight line add up to 180° always
180° - 94° = x° = 86°
<span> D) Train A by a factor of 1.1
</span>Train A: <span>17/35</span><span> = 34.6</span>
<span>Train B: </span>Rate<span> is the </span>slope<span> of the </span>equation, 31.35
Thus,<span>34.6/31.35</span><span> = 1.1036</span>
