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3 years ago

What is the GCF of 33 and 55?

1 answer:

4 0

The factors of 33 are 1, 3, 11, and 33 .

The factors of 55 are 1, 5, 11, and 55 .

The common factors of 33 and 55 are 1 and 11 .

The greatest one is 11 .

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3 years ago

State the conclusion based on the results of the test. The standard deviationstandard deviation inin the pressure required to op

inysia [295]

Answer:

B. There is sufficient evidence that the mean of the pressure required to open a certain valve has changed.

Step-by-step explanation:

We make this conclusion based on these reasons:

We are told that the "null hypothesis was rejected" after the "manager feels that the pressure variability has changed., meaning the null hypothesis was the opposite of what occurred; that is to say, it is the alternate hypothesis that proved true instead.
"changes in the manufacturing process" form what can be called "sufficient evidence" that the mean of the pressure required to open the valve has changed, thereby going against the null hypothesis.

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3 years ago

What is true about the dilation?

IrinaK [193]

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3 years ago

A certain unsavory bar for poker-playing dogs is attended by only two types of dogs: "good dogs" and "bad dogs." For a randomly

SVETLANKA909090 [29]

Answer: The required probability is 0.1923.

Step-by-step explanation:

Since we have given that

Probability that it's a good dog = 0.4

Probability that it's a bad dog = 1-0.4 = 0.6

Probability that the dog smokes given that its a bad dog = 0.7

Probability that it smokes given that its a good dog = 0.25

According to question, probability of smoking pipe would be

P(good).P(Smoking pipe|good)+P(bad).P(smoking pipe|bad)

$0.4\times 0.25+0.6\times 0.7\\\\=0.1+0.42\\\\=0.52$

So, Probability of getting a good dog given that it is smoking pipe is given by

$\dfrac{P(good).P(smoking\ pipe|good)}{P(smoking\ pipe)}\\\\=\dfrac{0.4\times 0.25}{0.52}\\\\=\dfrac{0.1}{0.52}\\\\=0.1923$

Hence, the required probability is 0.1923.

3 0

3 years ago

Read 2 more answers

Determine the sum of the arithmetic series: 5+18 +31 +44 + ... 161.

Finger [1]

Answer:

1079

Step-by-step explanation:

Hello,

18-5 = 13

31-18=13

44-31=13

161=5+13*12

So we need to compute

$\displaystyle \sum_{k=0}^{k=12} \ {(5+13k)}\\\\=\sum_{k=0}^{k=12} \ {(5)} + 13\sum_{k=1}^{k=12} \ {(k)}\\\\=13*5+13*\dfrac{12*13}{2}\\\\=65+13*13*6\\\\=65+1014\\\\=1079$

Thanks

3 0

4 years ago