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erik [133]
3 years ago
8

Jaylen and six of her younger siblings have ages that are consecutive. When they moved from San Francisco to Chicago, their ages

(all seven of them) added up to 91. How old was Jaylen when they moved? Explain your thinking.
Mathematics
1 answer:
Otrada [13]3 years ago
3 0

Answer:

Jaylen was 16 years old. She's the oldest.

Step-by-step explanation:

16  Jaylen

15  sibling 1

14  sibling 2

13  sibling 3

12 sibling 4

11  sibling 5

10  sibling 6

____________

91  Total

My thinking was that I started out dividing 91 by 7. That came out 13. So I knew the oldest one had to be older than 13.

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It is estimated that 75% of all young adults between the ages of 18-35 do not have a landline in their homes and only use a cell
Mademuasel [1]

Answer:

a) 75

b) 4.33

c) 0.75

d) 3.2 \times 10^{-13} probability that no one in a simple random sample of 100 young adults owns a landline

e) 6.2 \times 10^{-61} probability that everyone in a simple random sample of 100 young adults owns a landline.

f) Binomial, with n = 100, p = 0.75

g) 4.5 \times 10^{-8} probability that exactly half the young adults in a simple random sample of 100 do not own a landline.

Step-by-step explanation:

For each young adult, there are only two possible outcomes. Either they do not own a landline, or they do. The probability of an young adult not having a landline is independent of any other adult, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

75% of all young adults between the ages of 18-35 do not have a landline in their homes and only use a cell phone at home.

This means that p = 0.75

(a) On average, how many young adults do not own a landline in a random sample of 100?

Sample of 100, so n = 100

E(X) = np = 100(0.75) = 75

(b) What is the standard deviation of probability of young adults who do not own a landline in a simple random sample of 100?

\sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{100(0.75)(0.25)} = 4.33

(c) What is the proportion of young adults who do not own a landline?

The estimation, of 75% = 0.75.

(d) What is the probability that no one in a simple random sample of 100 young adults owns a landline?

This is P(X = 100), that is, all do not own. So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 100) = C_{100,100}.(0.75)^{100}.(0.25)^{0} = 3.2 \times 10^{-13}

3.2 \times 10^{-13} probability that no one in a simple random sample of 100 young adults owns a landline.

(e) What is the probability that everyone in a simple random sample of 100 young adults owns a landline?

This is P(X = 0), that is, all own. So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{100,0}.(0.75)^{0}.(0.25)^{100} = 6.2 \times 10^{-61}

6.2 \times 10^{-61} probability that everyone in a simple random sample of 100 young adults owns a landline.

(f) What is the distribution of the number of young adults in a sample of 100 who do not own a landline?

Binomial, with n = 100, p = 0.75

(g) What is the probability that exactly half the young adults in a simple random sample of 100 do not own a landline?

This is P(X = 50). So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 50) = C_{100,50}.(0.75)^{50}.(0.25)^{50} = 4.5 \times 10^{-8}

4.5 \times 10^{-8} probability that exactly half the young adults in a simple random sample of 100 do not own a landline.

8 0
3 years ago
Joan receives a $7 weekly allowance plus $6 for each hour she helps her father paint. Ernie writes the equa on to represent the
zalisa [80]
C... hope this will help!
7 0
4 years ago
Read 2 more answers
ANSWER ASAP The area of a rectangle depends on its length and width. For the area to remain constant, the length varies inversel
Free_Kalibri [48]
Area of the rectangle is equal to length times width

In function notation, the Area of the rectangle function is a function in variables l (length) and w(width) as follows:

A(l, w)= l*w

for A=475 we have,

l*w=475

l= \frac{475}{w} or w= \frac{475}{l} , each are equivalent, and each represent the inverse variation.


Answer: l= \frac{475}{w} , w= \frac{475}{l} 


4 0
3 years ago
If someone flips switches on the selection in a completely random fashion, what is the probability that the system selected cont
DiKsa [7]
 Given that a display allows a customer to hook together any selection of components, one of each type. These are the types:
Receiver: Kenwood, Onkyo, Pioneer, Sony, Sherwood
CD player: Onkyo, Pioneer, Sony, Technics
Speakers: Boston, Infinity, Polk
Cassette: Onkyo, Sony, Teac, Technics:

Part (a):
In how many ways can one component of each type be selected?

The number of ways one type of receiver will be selected is given by 5C1 = 5
The number of ways one type of CD player will be selected is given by 4C1 = 4
The number of ways one type of speakers will be selected is given by 3C1 = 3
The number of ways one type of cassette will be selected is given by 4C1 = 4

Therefore, the number of ways one component of each type can be selected is given by 5 x 4 x 3 x 4 = 240 ways



Part (b):
In how many ways can components be selected if both the receiver and the compact disc player are to be Sony?

The number of ways of selecting a Sony receiver is 1
The number of ways of selecting a Sony CD player is 1
The number of ways one type of speakers will be selected is given by 3C1 = 3
The number of ways one type of cassette will be selected is given by 4C1 = 4

Therefore, the number of ways components can be selected if both the receiver and the compact disc player are to be Sony is given by 1 x 1 x 3 x 4 = 12



Part (c)
In how many ways can components be selected if none of them are Sony?

The number of ways one type of receiver that is not Sony will be selected is given by 4C1 = 4
The number of ways one type of CD player that is not Sony will be selected is given by 3C1 = 3
The number of ways one type of speakers that is not Sony will be selected is given by 3C1 = 3
The number of ways one type of cassette that is not Sony will be selected is given by 3C1 = 3

Therefore, the number of ways that components can be selected if none of them are Sony is given by 4 x 3 x 3 x 3 = 108



Part (d):
In how many ways can a selection be made if at least one Sony component is to be included?

The total number of ways of selecting one component of each type is 240
The number of ways that components can be selected if none of them are Sony is 108

Therefore, the number of ways of selecting at least one Sony component is given by 240 - 108 = 132



Part (e):
If someone flips switches on the selection in a completely random fashion, what is the probability that the system selected contains at least one Sony component?

The total number of ways of selecting one component of each type is 240
The number of ways of selecting at least one Sony component is 132

Therefore, the probability that a system selected at random contains at least one Sony component is given by 132 / 240 = 0.55



Part (f):
If someone flips switches on the selection in a completely random fashion, what is the probability that the system selected contains exactly one Sony component? (Round your answer to three decimal places.)

The number of ways of selecting only a Sony receiver is given by 1 x 3 x 3 x 3 = 27
The number of ways of selecting only a Sony CD player is given by 4 x 1 x 3 x 3 = 36
The number of ways of selecting only a Sony cassette is given by 4 x 3 x 3 x 1 = 36

Thus, the number of ways of selecting exactly one Sony component is given by 27 + 36 + 36 = 99

Therefore, the probability that a system selected at random contains exactly one Sony component is given by 99 / 240 = 0.413
5 0
4 years ago
Ln (3x+1)-ln (5+x) = ln 2
RideAnS [48]
First you would simplify the left side to get,

ln( ( 3x+1 ) / ( 5+x ) ) = ln 2

Then raise both sides as the power of e, so it would basically cancel out the ln's.

3x+1 / 5+x = 2

3x+1 = 2( 5+x )

3x+1 = 10+2x

x = 9
3 0
3 years ago
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