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3 years ago

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A sheet of paper is 8.25 inches wide by 11.3 inches long. What is the area of the front of the paper? 93.225 square inches 94.08

5 square inches 99.505 square inches 136.97 square inches

1 answer:

g100num [7]3 years ago

3 0

Step-by-step explanation:

area is just multiply both of the numbers together

so

8.25*11.3=93.225sqin²

answer is 93.225sqin²

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Jess walked from her home to her friend’s house and arrived at 4.15. If it took Jess 25 minutes to walk this distance, then what

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D.3:50

Count back 25 minutes from 4:15 and you’ll get 3:50. The numbers on the clock are 5 minutes apart. It should be easy to solve just by using a standard clock

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A person x inches tall has a pulse rate of y beats per minute, as given approximately by yequals600 x Superscript negative 1 di

tankabanditka [31]

Answer:

a) 5.13beats/min

b) 2.82 beats/min

Step-by-step explanation:

Given the pulse rate of a person modelled by the equation y = 600x^-1/3 for 30≤x≤75

If the height is 39inches, the instantaneous rate of change of pulse rate for the heights will be expressed as;

y = 600(39)^-1/3

y = {600(1/39)}/3

y = 600/39×3

y = 600/117

y ≈ 5.13beats/min

The instantaneous rate for a 39 inches tall person is 5.13 beats per min

b) For a 71inches tall person, the beat rate will be expressed as;

y = 600(71)^-1/3

y = {600(1/71)}/3

y = 600/71×3

y = 600/213

y ≈ 2.82 beats per minute

The instantaneous rate for a 71 inches tall person is 2.82 beats per min

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3 years ago

Carrie and brent leave home at the same time. carrie drives due east at a rate of 30 mph, while brent drives due south at a rate

Helga [31]

<h3>They are 268 miles far apart after 4 hours</h3>

<h3>Further explanation</h3>

Acceleration is rate of change of velocity.

$\large {\boxed {a = \frac{v - u}{t} } }$

$\large {\boxed {d = \frac{v + u}{2}~t } }$

<em>a = acceleration ( m/s² )</em>

<em>v = final velocity ( m/s )</em>

<em>u = initial velocity ( m/s )</em>

<em>t = time taken ( s )</em>

<em>d = distance ( m )</em>

Let us now tackle the problem !

<u>Given :</u>

v₁ = 30 mph due east

v₂ = 60 mph due south

t = 4 hours

<u>Unknown :</u>

displacement = d = ?

<u>Solution :</u>

$d_1 = v_1 \times t$

$d_1 = 30 ~ mph \times 4 ~ h$

$d_1 = \boxed {120 ~ miles}$

$d_2 = v_2 \times t$

$d_2 = 60 ~ mph \times 4 ~ h$

$d_2 = \boxed {240 ~ miles}$

$d^2 = (d_1)^2 + (d_2)^2$

$d^2 = 120^2 + 240^2$

$d^2 = 72000$

$d = \sqrt{72000}$

$d = 120\sqrt{5} ~ miles$

$d \approx \boxed {268 ~ miles}$

<h2>Conclusion :</h2><h3>They are 268 miles far apart after 4 hours</h3>

<h3>Learn more</h3>

Velocity of Runner : brainly.com/question/3813437
Kinetic Energy : brainly.com/question/692781
Acceleration : brainly.com/question/2283922
The Speed of Car : brainly.com/question/568302

<h3>Answer details</h3>

Grade: High School

Subject: Physics

Chapter: Kinematics

Keywords: Velocity , Driver , Car , Deceleration , Acceleration , Obstacle , Speed , Time , Rate

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I need help with this question

Lunna [17]

{3,4,5,6} should be the answer

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3 years ago

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zhenek [66]

Answer:

$P(Gray\ and\ Blue) = \frac{1}{4}$

Step-by-step explanation:

Given

$Sections = 10$

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$n(Blue) = 5$

Required

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Using probability formula;

$P(Gray\ and\ Blue) = P(Gray) * P(Blue)$

Calculating P(Gray)

$P(Gray) = \frac{n(Gray)}{Sections}$

$P(Gray) = \frac{5}{10}$

$P(Gray) = \frac{1}{2}$

Calculating P(Gray)

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$P(Blue) = \frac{5}{10}$

$P(Blue) = \frac{1}{2}$

Substitute these values on the given formula

$P(Gray\ and\ Blue) = P(Gray) * P(Blue)$

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$P(Gray\ and\ Blue) = \frac{1}{4}$

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3 years ago