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4 years ago

Which two subatomic particles are located in the nucleus of an atom?

Chemistry

2 answers:

Nostrana [21]4 years ago

7 0

The two subatomic particles located inside the nucleus of an atom are the NEUTRONS and PROTONS. The electrons are located in the electron cloud.

Lapatulllka [165]4 years ago

3 0

Answer : The two subatomic particles located in the nucleus of an atom are, protons and neutrons.

Explanation :

As we know that an atom is the smallest unit of a matter that consist of three subatomic particles which are electrons, protons and neutrons.

The protons and the neutrons are located inside the nucleus or center of the nucleus where the mass of the an atom is concentrated and the electrons are located around the nucleus.

The protons are positively charged, the electrons are negatively charged and the neutrons are neutral that means it has no charge.

Hence, the two subatomic particles located in the nucleus of an atom are, protons and neutrons.

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Which formula represents lead(II) hydroxide?

frez [133]

Pb(OH)2

This is the formula

5 0

3 years ago

On the basis of molecular structure and bond polarity, which of the following compounds is most likely to have the greatest solu

Drupady [299]

Answer:

$\boxed{\text{c) NH$_{3}$; hydrogen bonding}}$

Explanation:

For each of these molecules, you must determine their VSEPR structure and then identify the strongest intermolecular forces.

Remember that water is a highly polar molecule.

a) CH₄

Electron geometry: tetrahedral

Molecular geometry: tetrahedral

Bond polarity: C-H bond nonpolar

Molecular polarity: nonpolar

Strongest IMF: London dispersion forces

Solubility in water: low

A nonpolar molecule is insoluble in a polar solvent.

b) CCl₄

Electron geometry: tetrahedral

Molecular geometry: tetrahedral

Bond polarity: C-Cl bond nonpolar

Molecular polarity: nonpolar (symmetrical molecule. All bond dipoles cancel)

Strongest IMF: London dispersion forces

Solubility in water: low

A nonpolar molecule is insoluble in a polar solvent.

d) PH₃

Electron geometry: tetrahedral

Molecular geometry: trigonal pyramidal

Bond polarity: P-H bonds are polar

Molecular polarity: polar (all P-H bond dipoles point towards P)

Strongest IMF: dipole-dipole

Solubility in water: soluble

A polar molecule is soluble in a polar solvent.

c) NH₃

Electron geometry: tetrahedral

Molecular geometry: trigonal pyramidal

Bond polarity: N-H bonds are highly polar

Molecular polarity: highly polar (all N-H bond dipoles point towards N)

Strongest IMF: hydrogen bonding

Solubility in water: highly soluble

NH₃ is so polar that it can form hydrogen bonds with water.

$\boxed{\textbf{The compound with the greatest solubility in water is NH$_{3}$}}$

8 0

3 years ago

Answer #2 for 10 points!

-BARSIC- [3]

a. i,ii,vi

b.iv,v,iii

3 0

4 years ago

When 240 mg of a certain molecular compound X are dissolved in 35.0 g of dibenzyl ether ((C6H5CH2)2O), the freezing point of the

DedPeter [7]

Answer: MM = 16.55 g/mol

Explanation: Freezing point depression is a phenomena that explains why adding a solute to a solvent decreases the solvent freezing point: when a substance begins to freeze, its molecules slows down and rearrange itself forming a solid. If a solute is added, the molecules from the solvent interfere in the formation of the solid. To guarantee the transformation, the solution has to cooled down even more.

Freezing point and molality concentration is related by

$\Delta T=T_{f}_{(solvent)}-T_{f}_{(solution)}=K_{f}.m$

where

ΔT is freezing point depression

$T_{f}_{(solvent)}$ and $T_{f}_{(solution)}$ are freezing point of solvent and solution, respectively

$K_{f}$ is freezing point depression constant

m is molality concentration

Dibenzyl ether is the solvent and has the following properties: $K_{f}=$ 6.27 and $T_{f}$ = 3.6°C.

Molality concentration is

$m=\frac{T_{(solvent)}-T_{(solution)}}{K_{f}}$

$m=\frac{3.6-1}{6.27}$

m = 0.415

Molality concentration is moles (n) of solute dissolved in a mass, in kilogram, of solvent.

$m=\frac{moles}{mass(kg)}$

n = m(mass of solvent in kg)

n = 0.415(0.035)

n = 0.0145

Molar mass (M) is the weight of one sample mole and can be calculated as

$n=\frac{m}{M}$

M = $\frac{m}{n}$

m in grams

Molar mass of compound X is

$M=\frac{0.24}{0.0145}$

M = 16.55

Molar mass of molecular compound X is 16.55g/mol

3 0

3 years ago

Write the ions present in a solution of na3po4. express your answers as chemical formulas separated by a comma. offset subscript

spin [16.1K]

Sodium/natrium is a metal from first column group so it should have one 1+ charge. Phosphate ion has 3- charge. That is why there 3 natrium ion for 1 phosphate ion when this molecule is dissolved in water. The ion formula would be:

(Na) $_{3}$ (PO $_{4}$ ) ==> 3 Na $^{1+}$ + PO $_{4} ^{3-}$

6 0

4 years ago