The sector COB is cut from the circle with center O. The ratio of the area of the sector removed from the whole circle to the ar
ea of the sector removed from the inner circle is R^2/r^2 .
1 answer:
Answer:

Step-by-step explanation:
Given
See attachment for circles
Required
Ratio of the outer sector to inner sector
The area of a sector is:
For the inner circle

The sector of the inner circle has the following area

For the whole circle

The sector of the outer sector has the following area

So, the ratio of the outer sector to the inner sector is:


Cancel out common factor

Express as fraction

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Y÷1 =y
answer : y
because 1y means 1 times y
First let us find


Now let;s solve the second part
V=1/3*πr² *h,
raduus r=32/2=16
V=1/3*3.14*(16)² *18=6*3.14*(16)² =4823.04
Answer:
Doesn't make sense.
Step-by-step explanation:
-1 ≤ cosθ ≤ 1
=> cosθ = 3√3 doesn't make sense.
C. −6, is the best option