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2 years ago

The legs of a right triangle measure 6 inches and 11 inches.

Mathematics

1 answer:

eduard2 years ago

3 0

Answer:

$28.6\textdegree$

Step-by-step explanation:

The legs of right triangles are $6\ inches\ and\ 11\ inches$ .

The smallest angle will be the angle opposite to smallest side. Here smallest angle will be angles opposite to the leg of length of $6\ inches$ .

Let the angle is $\theta$ .

$\tan \theta=\frac{oppsite}{adjacent}\\\\\tan \theta=\frac{6}{11}\\\\\theta=\tan^{-1}(\frac{6}{11})\\\\\tehta=28.61\approx 28.6\textdegree$

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What is the area of the following circle with radius of 7

seropon [69]

Answer:

153.94

Step-by-step explanation:

$\pi r^{2}\\\pi (7)^2\\=153.94--->$ about this amount

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2 years ago

1. You are going to make one of these bags from a roll of cloth 1 meter wide. What

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Answer:

1 cm

You are going to make one of these bags from a roll of cloth 1 meter wide. What

is the shortest length that you need to cut from the roll for the bag?

Step-by-step explanation:

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1 year ago

A survey in Men’s Health magazine reported that 39% of cardiologists said that they took vitamin E supplements. To see if this i

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Answer:

$z=\frac{0.36 -0.39}{\sqrt{\frac{0.39(1-0.39)}{100}}}=-0.615$

The p value for this case would be:

$p_v =2*P(z$

For this case since the p value is higher than the significance level we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true proportion is not different from 0.39

Step-by-step explanation:

Information given

n=100 represent the random sample taken

X=36 represent the number of people that take E supplement

$\hat p=\frac{36}{100}=0.36$ estimated proportion of people who take R supplement

$p_o=0.39$ is the value that we want to test

$\alpha=0.05$ represent the significance level

z would represent the statistic

$p_v$ represent the p value

Hypothesis to test

We want to test if the true proportion is equatl to 0.39 or not, the system of hypothesis are.:

Null hypothesis: $p=0.39$

Alternative hypothesis: $p \neq 0.39$

The statistic is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

Replacing the info we got:

$z=\frac{0.36 -0.39}{\sqrt{\frac{0.39(1-0.39)}{100}}}=-0.615$

The p value for this case would be:

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2 years ago

Assume that thermometer readings are normally distributed with a mean of degrees and a standard deviation of 1.00degrees C. A th

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Answer:

0.2684 is the probability that the temperature reading is between 0.50 and 1.75.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 0 degrees

Standard Deviation, σ = 1 degrees

We are given that the distribution of thermometer readings is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

P(Between 0.50 degrees and 1.75 degrees)

$P(0.50 \leq x \leq 1.75)\\\\ = P(\displaystyle\frac{0.50 - 0}{1} \leq z \leq \displaystyle\frac{1.75-0}{1})\\\\ = P(0.50 \leq z \leq 1.75)\\= P(z \leq 1.75) - P(z < 0.50)\\= 0.9599 - 0.6915 = 0.2684 = 26.84\%$

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2 years ago

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zhenek [66]

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2 years ago