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3 years ago

The legs of a right triangle measure 6 inches and 11 inches.

Mathematics

1 answer:

eduard3 years ago

3 0

Answer:

$28.6\textdegree$

Step-by-step explanation:

The legs of right triangles are $6\ inches\ and\ 11\ inches$ .

The smallest angle will be the angle opposite to smallest side. Here smallest angle will be angles opposite to the leg of length of $6\ inches$ .

Let the angle is $\theta$ .

$\tan \theta=\frac{oppsite}{adjacent}\\\\\tan \theta=\frac{6}{11}\\\\\theta=\tan^{-1}(\frac{6}{11})\\\\\tehta=28.61\approx 28.6\textdegree$

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1. A non-oraganic cleaner is 95% effective
2. An organic cleaner is 90% effective
3. Therefore, </span><span>an organic cleaner is not as effective as a non-organic cleaner in killing germs that cause colds and the flu.</span>

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3 years ago

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Evgen [1.6K]

Answer:

$\displaystyle 8$

Step-by-step explanation:

we would like to compute the following limit

$\displaystyle \lim_{x \to 16} \left( \frac{x - 16}{ \sqrt{x} - 4} \right)$

if we substitute 16 directly we'd end up

$\displaystyle = \frac{16 - 16}{ \sqrt{16} - 4}$

$\displaystyle = \frac{0}{ 0}$

which isn't a good answer now notice that we have a square root on the denominator so we can rationalise the denominator to do so multiply the expression by √x+4/√x+4 which yields:

$\displaystyle \lim_{x \to 16} \left( \frac{x - 16}{ \sqrt{x} - 4} \times \frac{ \sqrt{x} + 4 }{ \sqrt{x} + 4 } \right)$

simplify which yields:

$\displaystyle \lim_{x \to 16} \left( \frac{(x - 16)( \sqrt{x} + 4)}{ x - 16} \right)$

we can reduce fraction so that yields:

$\displaystyle \lim_{x \to 16} \left( \frac{ \cancel{(x - 16)}( \sqrt{x} + 4)}{ \cancel{x - 16} } \right)$

$\displaystyle \lim _{x \to 16} \left( \sqrt{x } + 4\right)$

now it's safe enough to substitute 16 thus

substitute:

$\displaystyle = \sqrt{16} + 4$

simplify square root:

$\displaystyle = 4 + 4$

simplify addition:

$\displaystyle = 8$

hence,

$\displaystyle \lim_{x \to 16} \left( \frac{x - 16}{ \sqrt{x} - 4} \right) = 8$

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3 years ago

At the local clothing store 3 similar shirts and 4 similar jackets cost $360. 1 shirt and 3 jackets cost $220. Find the cost of

notsponge [240]

To solve this problem, it is easiest to set up a system of equations. Let's let the variable s represent the cost of a shirt and the variable j represent the cost of jackets. According to the given information, we can set up the following equations (because cost multiplied by quantity yields price):

3s + 4j = 360

1s + 3j = 220

Next, we can manipulate the second equation so that it equals s in terms of j. We do this by subtracting 3j from both sides of the equation, as shown below:

s = 220 - 3j

After that, we should substitute in this value for the variable s in the first equation.

3(220-3j) + 4j = 360

Next, we should use the distributive property to simplify the left side of the equation.

660 - 9j + 4j = 360

Then, we should simplify the left side of the equation by combining like terms.

660 - 5j = 360

After, we can subtract 660 from both sides of the equation to get the variable term alone.

-5j = -300

Finally, we should divide both sides of the equation by -5 in order to get the variable j alone.

j = 60

Now that we know the value of the variable j, we should substitute this value into one of the original equations and solve using division and subtraction to isolate the variable.

3s + 4j = 360

3s + 4(60) = 360

3s + 240 = 360

3s = 120

s = 40

Therefore, the cost of one shirt is $40.

Hope this helps!

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3 years ago

Using the fixed-time period inventory model, and given an average daily demand of 200 units, 4 days between inventory reviews, 5

KATRIN_1 [288]

Answer:

Correct option: B. About 1,686.

Step-by-step explanation:

The formula to compute the order quantity (Q) is:

$Q=(q_{d}\times (I+L))+(z\times\sigma_{I+L})-I_{n}$

Here

$q_{d}=average\ daily\ semand=200\\I = Inventory\ review\ time=4\\L=lead\ time=5\\\sigma_{I+L}=standard\ deviation\ over\ the\ review\ and\ lead\ time=3\\I_{n}=number\ of\ units\ of\ inventory\ on\ hand=120$