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podryga [215]
4 years ago
5

How do I solve what is 2/3 of 90

Mathematics
2 answers:
masya89 [10]4 years ago
6 0

Answer:

Thus, \frac{2}{3}\times 90=60

Step-by-step explanation:

Given: \frac{2}{3} of 90

We have to write the simplified form of \frac{2}{3} of 90

Consider the given expression

\frac{2}{3} of 90

of means multiplication

thus, \frac{2}{3} of 90 means \frac{2}{3}\times 90

Simplify, we have,

2\times 30=60

Thus, \frac{2}{3}\times 90=60

Sergeu [11.5K]4 years ago
3 0
<span>The answer is 60.

Explanation<span>:
In mathematics, the word "of" indicates multiply. This means we would multiply 2/3 * 90.

We can write 90 as a fraction by putting it over 1, which gives us 2/3(90/1).

To multiply fractions, we multiply straight across: (2*90)/(3*1) = 180/3 = 60.</span></span>
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Identify each expression that represents the slope of a tangent to the curve y=1/x+1 at any point (x,y) .
tankabanditka [31]

Answer:

Slope of a tangent to the curve = f'(x) = \frac{-1 }{(x+1)^{2} }

Step-by-step explanation:

Given - y = 1/x+1

To find - Identify each expression that represents the slope of a tangent to the curve y=1/x+1 at any point (x,y) .

Proof -

We know that,

Slope of tangent line = f'(x) = \lim_{h \to 0} \frac{f(x+h) - f(x)}{h}

We have,

f(x) = y = \frac{1}{x+1}

So,

f(x+h) = \frac{1}{x+h+1}

Now,

Slope = f'(x)

And

f'(x) =  \lim_{h \to 0} \frac{f(x+h) - f(x)}{h}  \\= \lim_{h \to 0} \frac{\frac{1}{x+h+1}  - \frac{1}{x+1} }{h}\\= \lim_{h \to 0} \frac{x+1 - (x+h+1) }{h(x+1)(x+h+1)}\\= \lim_{h \to 0} \frac{x +1 - x-h-1 }{h(x+1)(x+h+1)}\\= \lim_{h \to 0} \frac{-h }{h(x+1)(x+h+1)}\\= \lim_{h \to 0} \frac{-1 }{(x+1)(x+h+1)}\\=  \frac{-1 }{(x+1)(x+0+1)}\\=  \frac{-1 }{(x+1)(x+1)}\\=  \frac{-1 }{(x+1)^{2} }

∴ we get

Slope of a tangent to the curve = f'(x) = \frac{-1 }{(x+1)^{2} }

6 0
3 years ago
Select the correct answer from each drop-down menu.
9966 [12]

Answer:

(0.392 ; 0.508)

Step-by-step explanation:

Given that :

p = 45% = 0.45

α = 1 - 90% = 0.1

Zα/2 = Z0.01/2 = Z0.05 = 1.645 (from Z standard table).

Using the relation :

p ± Z0.05*sqrt((p(1-p))/n)

p ± 1.645 * sqrt(0.45(0.55)/200)

p ± 1.645 * sqrt(0.0012375)

p ± 1.645 *0.0351781

0.45 - (1.645 * 0.0351781) = 0.3921320255

0.45 + (1.645 * 0.0351781) = 0.5078679745

(0.392 ; 0.508)

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