16 I think could be wrong
Calculate the z-score first.
with "s" being the standard deviation within the sample of n=4 and being the sample mean.
So
Note the absolute value - it takes care of a difference in both directions (sample mean being lower and higher) but we need to keep it mind when looking up the z values in tables - we must choose the "two-tailed test" table.
Now, look up the required z value for alpha=0.05: z>=1.96 (using a two-tailed table).
So our z would have be >=1.96 for the evidence to be significant at the required level of 0.05. The calculated value falls far short at 0.5. Therefore there is no evidence for a significant treatment effect, given the data/sample.
Answer:
14
Step-by-step explanation:
Answer:
a) It is a one-tailed test
Step-by-step explanation:
The number of plants he sets up in the room, n = 20
The number of plants that grew more with Miracle Grow = 14
The alpha level α = 0.01
A one-tailed test is used when the critical-area of interest in the distribution is either to the left or right of a value on the number line. That is the test is concerned if the test result is either less than or more than a value
In the test the farmer subjects all 20 plants to the same test treatment without any control experiment, therefore, the farmer evaluates the plants based on how much they grow compared to each other, that is if they grow more or less than their pairs
Therefore a one-tailed test should be used.