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3 years ago

Plz answer this question

Mathematics

1 answer:

sergiy2304 [10]3 years ago

4 0

Answer:

Step-by-step explanation:

Each digit in a whole number has a place value, based on its position from the decimal point.

The place value of a digit increases by a factor of 10 as we move left on the place value chart and decreases by a factor of 10 as we move right.

Numbers to the left of the decimal point increase in place value in the order: ones, tens, hundreds, etc.

The value of a digit is the digit multiplied by its place value.

So, the digit 3 in 731.8 has a value of 30.

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Simplify the expression:<br> 2x+1bx8

denis-greek [22]

Answer:

2x+8b

Step-by-step explanation:

First since 1 and 8b are on the same side mutiply them:

1bx8=8b

So our new equation is 2x+8b

7 0

2 years ago

- 3/4 (x + 2) = 6<br> the / is a fraction can someone help

Oliga [24]

-3/4(x+2)=6
-3/4 is turned into a decimal, -0.75
-0.75(x+2)=6 distribute -0.75 to x and 2 (multiply)
-0.75x-1.5=6 add -1.5 under 6

-0.75x=7.5 divide -0.75 on both sides
-0.75x/-0.75 = 7.5/0.75
x=10

8 0

3 years ago

−2+pn/4 when n=5 and p=2.

Gnesinka [82]

Answer:

-2+5*2= -2+10/4

You get 8/4 which is 2

Step-by-step explanation:

6 0

2 years ago

Gloria works at least 10 hours per week but no more than 25 hours each week. She earns 9.00 an hour. Her weekly earnings depend

emmasim [6.3K]

Answer:

[90,225] notation or 135 range

Step-by-step explanation:

10x9=90

25x9=225

[900,2250] notation or 1350 range

7 0

3 years ago

If A and B are independent events with P(A) = .5 and P(B) = .2, find the following:a) P(A U B)b) P(A^c ? B^c)c) P(A^c U B^c)**No

Effectus [21]

If A and B are independent, then $P(A\cap B)=P(A)P(B)$ .

$P(A\cup B)=P(A)+P(B)-P(A\cap B)=P(A)+P(B)-P(A)P(B)$

$P(A\cup B)=0.5+0.2-0.5\cdot0.2$

$\boxed{P(A\cup B)=0.6}$

b. I'm guessing the ? is supposed to stand for intersection. We can use DeMorgan's law for complements here:

$P(A^c\cap B^c)=P(A\cup B)^c=1-P(A\cup B)$

$P(A^c\cap B^c)=1-0.6$

$\boxed{P(A^c\cap B^c)=0.4}$

c. DeMorgan's law can be used here too:

$P(A^c\cup B^c)=P(A\cap B)^c=1-P(A\cap B)=1-P(A)P(B)$

$P(A^c\cup B^c)=1-0.5\cdot0.2$

$\boxed{P(A^c\cup B^c)=0.9}$

4 0

3 years ago