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3 years ago

What does each sector in a circle graph represent?

Mathematics

1 answer:

pychu [463]3 years ago

3 0

Each sector in the graph is part of the whole data set

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A survey of 200 students is selected randomly on a large university campus. They are asked if they use a laptop in class to take

Lina20 [59]

Answer:

The 95% confidence interval for the true proportion of university students who use laptop in class to take notes is (0.2839, 0.4161).

Step-by-step explanation:

The (1 - α)% confidence interval for population proportion P is:

$CI=p\pm z_{\alpha/2}\sqrt{\frac{p(1- p)}{n}}$

The information provided is:

x = number of students who responded as"yes" = 70

n = sample size = 200

Confidence level = 95%

The formula to compute the sample proportion is:

$p=\frac{x}{n}$

The R codes for the construction of the 95% confidence interval is:

> x=70

> n=200

> p=x/n

> p

[1] 0.35

> s=sqrt((p*(1-p))/n)

> s

[1] 0.03372684

> E=qnorm(0.975)*s

> lower=p-E

> upper=p+E

> lower

[1] 0.2838966

> upper

[1] 0.4161034

Thus, the 95% confidence interval for the true proportion of university students who use laptop in class to take notes is (0.2839, 0.4161).

7 0

3 years ago

Read 2 more answers

On the map the distance between two towns is 10.5 centimeters. If 3 centimeters represents 90 miles what is the actual distance

Ainat [17]

Answer:

315 miles

Step-by-step explanation:

90 times 3 plus 45

3 0

3 years ago

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123÷6×7[(654+2)×(12÷3)]

melomori [17]

Answer:

Step-by-step explanation:

123/6 x 7[(654 + 2) x (12/3)].....do whats in parenthesis first

123/6 x 7[656 x 4] ......do whats in brackets

123/6 x 7(2624) ....do multiplication/division from left to right, whichever comes first

20.5 x 18,368 =

376544 <===

8 0

3 years ago

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At a fudge shop, they cut a sheet of fudge into one-ounce pieces.

il63 [147K]

Answer:

Step-by-step explanation:

4 0

2 years ago

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Differentiate the following functions (x^3+1)(x-2)÷x^2

Masja [62]

Given:

The given function is:

$\dfrac{(x^3+1)(x-2)}{x^2}$

To find:

The differentiation of the given function.

Solution:

Consider the given function,

$y=\dfrac{(x^3+1)(x-2)}{x^2}$

It can be written as:

$y=\dfrac{(x^3)(x)+(x^3)(-2)+(1)(x)+(1)(-2)}{x^2}$

$y=\dfrac{x^4-2x^3+x-2}{x^2}$

$y=\dfrac{x^4}{x^2}-\dfrac{2x^3}{x^2}+\dfrac{x}{x^2}-\dfrac{2}{x^2}$

$y=x^2-2x+\dfrac{1}{x}-\dfrac{2}{x^2}$

Differentiate with respect to x.

$y'=\dfrac{d}{dx}(x^2)-\dfrac{d}{dx}(2x)+\dfrac{d}{dx}(x^{-1})-\dfrac{d}{dx}\2(x^{-2})$

$y'=2x-2(1)+(-x^{-2})-2(-2x^{-3})$

$y'=2x-2-\dfrac{1}{x^2}+\dfrac{4}{x^3}$

Therefore, the differentiation of the given function is $2x-2-\dfrac{1}{x^2}+\dfrac{4}{x^3}$ .

8 0

3 years ago