12+9+15=36 cm. perimeter is basically all the sides added up together
<span>11,550 km has to be changed to 11,550,000 meters
G · m · t² = 4 · π² · r³ we can change that to
</span>t² = (4 · π² · r³) / <span>(G · m )
t^2 = 4*PI^2*r^3 / (G*m)
</span>t^2 = 4*PI^2*<span>(11,550,000)^3 / 6.67*10^-11*5.98*10^24kg
t^2 = </span>
<span>
<span>
<span>
6.083*10^22
</span>
</span>
</span>
<span><span>
</span>
</span>
/
<span>
<span>
<span>
3.9</span></span></span>9 * 10^14
t^2 =
<span>
<span>
<span>
152,500,000</span></span></span>
t = <span>12,350 seconds
</span>and its orbital distance it travels is 11,550 * 2*PI = 70,050 kilometers
Therefore, it is traveling at 70,050 km / 12,350 second which equals
5.67 km per second which <em>is 5,670 meters per second.</em>
Source:
http://www.1728.org/kepler3a.htm
A calculator can help you with that.
In radians, arcsin(sin(9π) / 7) = 0.
The justification for step 3 is incorrect. It should be x = 10/8.
Hope this helps =)
