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3 years ago

2x + 1 < 5

Mathematics

2 answers:

jasenka [17]3 years ago

7 0

For this case we have the following inequality:

$2x + 1$

Subtracting 1 from both sides of the inequality we have:

$2x$

Dividing between 2 on both sides of the inequality:

$x$

Thus, the solution is given by all values of "x" less than 2.

Answer:

$x$

Dmitry [639]3 years ago

6 0

Answer:

x < 2

Step-by-step explanation:

$2x+1$

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Step-by-step explanation:

Consider the given problem is

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$3\cdot \frac{\sqrt{7}}{\sqrt{25}}-\frac{\sqrt{28}}{\sqrt{25}}+\frac{\sqrt{63}}{\sqrt{25}}$ $[\because \sqrt{\frac{a}{b}}=\frac{\sqrt{a}}{\sqrt{b}}]$

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Taking out common factors.

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3 years ago