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3 years ago

I NEED URGENT HELP WITH THIS ONE

Mathematics

1 answer:

Ivenika [448]3 years ago

3 0

Answer:

Step-by-step explanation:

how urgent do you need help om thid, lowkey I'm craving some wings and much more other stuff

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Find the apothem and area of a square with a radius of 9.

Nonamiya [84]

Answer:

I think the answer is 18 square or 324.

Step-by-step explanation:

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3 years ago

2x - 1 = 0 is a quadratic equation. <br> True False

harina [27]

I believe the answer is false

Hope this helps

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3 years ago

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How many feet ate in 24 yards

baherus [9]

Answer: 72 feet

Step-by-step explanation: 1 yard is equal to 3 feet, so if there are 24 yards, we can multiply 24 by 3. This can be shown using the following formula: y · 3 = f (where y = number of yards and f = feet.) So:

24 · 3 = 72

8 0

3 years ago

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Rewrite the following integral in spherical coordinates.

lora16 [44]

In cylindrical coordinates, we have $r^2=x^2+y^2$ , so that

$z = \pm \sqrt{2-r^2} = \pm \sqrt{2-x^2-y^2}$

correspond to the upper and lower halves of a sphere with radius $\sqrt2$ . In spherical coordinates, this sphere is $\rho=\sqrt2$ .

$1 \le r \le \sqrt2$ means our region is between two cylinders with radius 1 and $\sqrt2$ . In spherical coordinates, the inner cylinder has equation

$x^2+y^2 = 1 \implies \rho^2\cos^2(\theta) \sin^2(\phi) + \rho^2\sin^2(\theta) \sin^2(\phi) = \rho^2 \sin^2(\phi) = 1 \\\\ \implies \rho^2 = \csc^2(\phi) \\\\ \implies \rho = \csc(\phi)$

This cylinder meets the sphere when

$x^2 + y^2 + z^2 = 1 + z^2 = 2 \implies z^2 = 1 \\\\ \implies \rho^2 \cos^2(\phi) = 1 \\\\ \implies \rho^2 = \sec^2(\phi) \\\\ \implies \rho = \sec(\phi)$

which occurs at

$\csc(\phi) = \sec(\phi) \implies \tan(\phi) = 1 \implies \phi = \dfrac\pi4+n\pi$

where $n\in\Bbb Z$ . Then $\frac\pi4\le\phi\le\frac{3\pi}4$ .

The volume element transforms to

$dx\,dy\,dz = r\,dr\,d\theta\,dz = \rho^2 \sin(\phi) \, d\rho \, d\theta \, d\phi$

Putting everything together, we have

$\displaystyle \int_0^{2\pi} \int_1^{\sqrt2} \int_{-\sqrt{2-r^2}}^{\sqrt{2-r^2}} r \, dz \, dr \, d\theta = \boxed{\int_0^{2\pi} \int_{\pi/4}^{3\pi/4} \int_{\csc(\phi)}^{\sqrt2} \rho^2 \sin(\phi) \, d\rho \, d\phi \, d\theta} = \frac{4\pi}3$

4 0

2 years ago

EXTRA POINTS * how do you graph y=2x + 1

ahrayia [7]

Step-by-step explanation:

first u need to pick a random coordinate to substitute the X . example 0

y = 2(0) + 1

y =1 , X= 0

X= 1

y= 2(1) + 1

y= 3, X= 1

then you continue this same process and again until u have at least two points to draw a straight line. it kinda depended if u want to fill the entire graph.

3 0

3 years ago