V1 = 80 km/hr
v2 = 60 km/hr
The speed of the car from point A is 80 km/hr while the speed of the car from point B is 60 km/hr.
Hope This Helps!
Answer:
m∠EJH = 212°
Step-by-step explanation:
The external angle (F) is half the difference of the arcs intercepted.
F = (EJH -EG)/2
Solving for EJH, we get ...
2F +EG = EJH
2(65°) +82° = m∠EJH = 212°
Answer:
He would be at the 15 yard line.
Step-by-step explanation:
The 40 yard gain would bring him to the 10 yard line (he caught it at the 50 yard line, so 50 - 40 = 10), but the 5 yards lost due to the tackle and push back would bring him to the 15 yard line (10 + 5 = 15).
60.6 would be temp. of her drink when she got back outside
Answer:
Step-by-step explanation:
tan Θ + tan 2Θ + √3 tan Θ tan 2Θ = √3
tan Θ + tan 2Θ = √3 - √3 tan Θ tan 2Θ
tan Θ + tan 2Θ = √3 ( 1 - tan Θ tan 2Θ)
(tan Θ + tan 2Θ) / (1 - tanΘ tan 2Θ) = √3
tan(Θ + 2Θ) = √3
tan 3Θ = tan () we know tan Θ = tan α; Θ = nΠ + α, n belongs to z
3Θ = nΠ + Π/3
Θ = nπ/3 + Π/9 for all n in Z