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Lina20 [59]
3 years ago
12

Can someone explain to me how to do this?

Mathematics
1 answer:
elena55 [62]3 years ago
6 0
In the slope intercept form equation of a line (y=ax+b) a represents the slope, and b represents the intercept, which is -5. Thus, we know y=ax-5. The slope can be found by creating a fraction with the change in y value on top, and the change of x value on the bottom. If we have two points (4, 1) and (0, -5) we can put this into a fraction - \frac{-5-1}{0-4}, which simplifies down to -6/-4, or 3/2. Thus the answer is f(x)=\frac{3}{2}x-5<span />
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If g( n ) = 3 n - 2, then what is the value of g(10)?
Paul [167]
The correct answer is 28
6 0
3 years ago
3x-13=74 solve for x
never [62]

Answer:

x=29

Step-by-step explanation:

3x-13=74

We want to solve for x, so we need to isolate it.

The first step is to add 13 to each side.

3x-13+13=74+13

3x = 87

Then we divide by 3 on each side

3x/3 = 87/3

x= 29

7 0
3 years ago
What is (x^-2 y^10)^2/x^5 y^-3 using only positive exponents
Eddi Din [679]

Answer:

\frac{(x^{ - 2}{y}^{10})^{2}  }{ {x}^{5}  {y}^{ - 3} }  \\   \frac{ {x}^{ - 4}  {y}^{20} }{ {x}^{5}  {y}^{ - 3  } }  \\   {x}^{ - 9}  {y}^{23} \\  \frac{ {y}^{23} }{ {x}^{9} }  \\ ans \: c

8 0
1 year ago
The volleyball team and the wrestling team at Stamford High School are having a joint car wash today,
Sedbober [7]

Answer:

Money raised by each team = 94 + 11 = <em>$105</em>

Number of cars washed = <em>11</em>

Step-by-step explanation:

Money already present with volleyball team = $50

Money raised by washing each car by volleyball team = $5

Let the number of cars washed = x

Money raised by washing cars = $5x

Money already present with volleyball team = $94

Money raised by washing each car by volleyball team = $1

Money raised by washing cars = $1x = $x

Given that, both the teams have raised same amount of money:

50+5x=94+x\\\Rightarrow 44=4x\\\Rightarrow x=11

Money raised by each team = 94 + 11 = <em>$105</em>

Number of cars washed = <em>11</em>

4 0
3 years ago
Solve the system: <br> 2/x - 3/y =-5; 4/x + 6\y =14
sertanlavr [38]

The solution is x = 2 \text{ and } y = \frac{1}{2}

<em><u>Solution:</u></em>

Let us assume,

a = \frac{1}{x}\\\\b = \frac{1}{y}

<em><u>Given system of equations are:</u></em>

\frac{2}{x} - \frac{3}{y} = -5

\frac{4}{x} + \frac{6}{y} = 14

<em><u>Rewrite the equation using "a" and "b"</u></em>

2a - 3b = -5 ------------ eqn 1

4a + 6b = 14 -------------- eqn 2

<em><u>Let us solve eqn 1 and eqn 2</u></em>

<em><u>Multiply eqn 1 by 2</u></em>

2(2a - 3b = -5)

4a - 6b = -10 ------------- eqn 3

<em><u>Add eqn 2 and eqn 3</u></em>

4a + 6b = 14

4a - 6b = -10

( - ) --------------------

8a = 4

a = \frac{4}{8}\\\\a = \frac{1}{2}

Substitute a = 1/2 in eqn 1

2(\frac{1}{2}) -3b = -5\\\\1 - 3b = -5\\\\3b = 6\\\\b = 2

Now let us go back to our assumed values

Substitute a = 1/2 in assumed values

a = \frac{1}{x}\\\\\frac{1}{2} = \frac{1}{x}\\\\x = 2

Substitute b = 2 in assumed value

b = \frac{1}{y}\\\\2 = \frac{1}{y}\\\\y = \frac{1}{2}

Thus the solution is x = 2 \text{ and } y = \frac{1}{2}

3 0
2 years ago
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