If 9/10 tons of gravel got spread over 3 feet, then how much gravel is on each foot? Well, it's a ratio.
9/10 tons : 3 ft
So, we divide each side of the ratio by 3.
3/10 tons : 1 ft.
So, that 3/10 tons of gravel on each foot of road.
Answer:
-12
Step-by-step explanation:
First, solve in parentheses.
2(-2-4)
=
2(-6)
Next, multiply 2 by -6.
Which equals -12.
So therefore using the distributive property shown above, the answer would be -12.
Hello,
"<" is transitive.
a<b
b<2 ==>a<b<2==>a<2
1/6^3 is also equivalent to 6^-3. It can be reverted back to 1/216. Answers on ed2020 are A. and D.
The value of GK = 18.6, GM = 14.5 AND JZ = 19.9.
From the figure:
MZ is a perpendicular bisector of ∆GHJ.
GM = MJ
GM = 14.5
KZ is a perpendicular bisector of ∆GHJ.
GK = KH
GK = 18.6
Z is the circumcenter of ∆GHJ.
JZ = GZ
JZ = 19.9
Therefore the value of GK = 18.6, GM = 14.5 AND JZ = 19.9.
Learn more about the perpendicular bisector here:
brainly.com/question/24753075
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