Let 1st integer = xLet 2nd integer = x + 1 We set up an equation. x(x + 1) = 195 x2 + x = 195 x2 + x - 195 = 0
We will use the quadratic formula: x = (-b ± √(b2 - 4ac) / (2a) x = (-1 ± √(1 - 4(-195))) / 2 x = (-1 ± √(781)) / 2 x = (-1 ± 27.95) / 2 x = 13.48x = -14.78
<span>We determine which value of x when substituted gives us a product of 195.</span> 13.48(14.48) = 195.19-14.48(-13.48) = 195.19 <span>The solution is 2 sets of two consecutive number</span> <span>Set 1</span> The 1st consecutive integer is 13.48The 2nd consecutive integer is 14.48
<span>Set 2</span> The 1st consecutive integer is -14.48The 2nd consecutive integer is -13.48Hopefully this helped, hard work lol :)
<span>
Can a function be concave down and positive everywhere?can be a semicircle
example, y=4+

attachment 1
Can a function be increasing and be concave down everywhere?no, concave down means increase slope then decrease slope
Can a function have two local extrema and three inflection points?inflection points are where the concavity changes
it can be at the ends, the middle and the other end
like in atachment 2, the circles are inflection points
Can a function have 4 zeros and two local extrema?
no, as you can see in attachment 3, there can be 3 zeroes at most for 2 local extrema
</span>
Answer: 
Step-by-step explanation:

Okay? We are going to need more information that that.