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Vlada [557]
3 years ago
13

Can someone help me on this

Mathematics
1 answer:
Vladimir79 [104]3 years ago
8 0

Answer:

7%

Step-by-step explanation:

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4 remainder 1 because six goes into twenty-five four times which is twenty-four and one more will make twenty five
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What is the name for fax like those in problem five
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A glazier is setting supports in parallel segments to prevent glass breakage during storms. What are the values of x and y? Just
lara [203]

Answer:

m∠y=50°

m∠x=50°

Step-by-step explanation:

we know that

The angles in matching corners are called <u><em>corresponding angles</em></u>. When the two lines are parallel Corresponding Angles are equal

so

m∠y=50° -----> by corresponding angles

and

The angles that are formed on opposite sides of the transversal and inside the two lines are <u><em>alternate interior angles</em></u>. When the lines are parallel, the alternate interior angles are equal.

so

m∠x=m∠y -----> by alternate interior angles

so

m∠x=50°

therefore

m∠y=50°

m∠x=50°

5 0
3 years ago
X
alex41 [277]

Answer:

y= x-3

Step-by-step explanation:

The points are ;(0, -3), (5,2), (7,4), (10,7).

Plot the coordinates on a graph tool to visualize the graph

Select two points to find the slope ; take point (5,2) and (10,7)

m=Δy/Δx

Δy = 7-2=5

Δx=10-5 = 5

m=5/5 =1

The equation of the graph will be;

m= Δy/Δx

1=y-4/x-7

x-7 = y-4

x-7+4=y

x-3=y

y= x-3

8 0
3 years ago
Match each equation with its solution set.
taurus [48]

Answer:

1- The solution of I2x + 5I = 9 is {-7 , 2}

2- The solution of I2x + 7I + 2 = 11 is {-8 , 1}

3- The solution of I5 - xI = 6 is {-1 , 11}

4- The solution of I6x - 8I + 7 = 5 is ∅

5- The solution of Ix + 3I = 12 is {-15 , 9}

6- The solution of Ix - 3I = -12 is ∅

Step-by-step explanation:

* At first lets explain the meaning of IxI = a

- If IxI = a ⇒ then x = a or x = -a

- IxI never give a negative answer, because IxI means the

 magnitude of x is always positive

Ex: I-2I is 2

* Now lets find the solution of each equation

1- ∵ I2x + 5I = 9

∴ 2x + 5 = 9 ⇒ subtract 5 from both sides

∴ 2x = 4 ⇒ divide both sides by 2

∴ x = 2

OR

∴ 2x + 5 = -9 ⇒ subtract 5 from both sides

∴ 2x = -14 ⇒ divide both sides by 2

∴ x = -7

* The solution of I2x + 5I = 9 is {-7 , 2}

2- ∵ I2x + 7I + 2 = 11 ⇒ Subtract 2 from both sides

∴ I2x + 7I = 9

∴ 2x + 7 = 9 ⇒ subtract 7 from both sides

∴ 2x = 2 ⇒ divide both sides by 2

∴ x = 1

OR

∴ 2x + 7 = -9 ⇒ subtract 7 from both sides

∴ 2x = -16 ⇒ divide both sides by 2

∴ x = -8

* The solution of I2x + 7I + 2 = 11 is {-8 , 1}

3- ∵ I5 - xI = 6

∴ 5 -x = 6 ⇒ subtract 5 from both sides

∴ -x = 1 ⇒ divide both sides by -1

∴ x = -1

OR

∴ 5 -x = -6 ⇒ subtract 5 from both sides

∴ -x = -11 ⇒ divide both sides by -1

∴ x = 11

* The solution of I5 - xI = 6 is {-1 , 11}

4- ∵ I6x - 8I + 7 = 5 ⇒ Subtract 7 from both sides

∴ I6x - 8I = -2

- I  I never give negative answer

* The solution of I6x - 8I + 7 = 5 is ∅

5- ∵ Ix + 3I = 12

∴ x + 3 = 12 ⇒ subtract 3 from both sides

∴ x = 9

OR

∴ x + 3 = -12 ⇒ subtract 3 from both sides

∴ x = -15

* The solution of Ix + 3I = 12 is {-15 , 9}

6- ∵ Ix - 3I = -12

- I  I never give negative answer

* The solution of Ix - 3I = -12 is ∅

4 0
3 years ago
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