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Ugo [173]
3 years ago
10

The sixth grade art students are making a mosaic using tiles in shapes of right triangles. Each tiles has the leg measures of 5.

2 cm and 6 cm. If there are 150 tiles in the mosaic, what is the area of the mosaic?
Mathematics
1 answer:
Drupady [299]3 years ago
5 0

Given:

Each right triangular tiles has the leg measures of 5.2 cm and 6 cm.

There are 150 tiles in the mosaic.

To find:

The area of the mosaic.

Solution:

We know that, the area of a triangle is:

A=\dfrac{1}{2}\times Base\times height

So, the area of Each right triangular tile is:

A=\dfrac{1}{2}\times 5.2\times 6

A=\dfrac{1}{2}\times 31.2

A=15.6

There are 150 tiles in the mosaic. So, the area of the mosaic is:

Area=15.6\times 150

Area=2340

Therefore, the total area of the mosaic is 2340 cm ².

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Step-by-step explanation:

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m = slope

b=  y intercept

Therefore, the slope is -3

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If Jamerra pays $450 simple interest in 2 years,
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3 0
4 years ago
Adrian kept an eye on the basketball game score by looking online every 10 minutes. Over the course of
Oduvanchick [21]

Answer:

Step-by-step explanation:

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4 0
2 years ago
Evaluate the function f(x) at the given numbers (correct to six decimal places). F(x) = x2 − 5x x2 − x − 20 , x = 5.5, 5.1, 5.05
exis [7]

we are given

f(x)=\frac{x^2-5x}{x^2-x-20}

Firstly, we will simplify it

f(x)=\frac{x(x-5)}{(x-5)(x+4)}

f(x)=\frac{x}{(x+4)}

At x=5.5:

we can plug x=5.5

f(5.5)=\frac{5.5}{(5.5+4)}

f(5.5)=0.578947

At x=5.1:

we can plug x=5.1

f(5.1)=\frac{5.1}{(5.1+4)}

f(5.1)=0.56043956

At x=5.05:

we can plug x=5.05

f(5.05)=\frac{5.05}{(5.05+4)}

f(5.05)=0.558011

At x=5.01:

we can plug x=5.01

f(5.01)=\frac{5.01}{(5.01+4)}

f(5.01)=0.5560488

At x=5.005:

we can plug x=5.005

f(5.005)=\frac{5.005}{(5.005+4)}

f(5.005)=0.5558023

At x=5.001:

we can plug x=5.001

f(5.001)=\frac{5.001}{(5.001+4)}

f(5.001)=0.5556049

At x=4.9:

we can plug x=4.9

f(4.9)=\frac{4.9}{(4.9+4)}

f(4.9)=0.5505617

At x=4.95:

we can plug x=4.95

f(4.95)=\frac{4.95}{(4.95+4)}

f(4.95)=0.5530726

At x=4.99:

we can plug x=4.99

f(4.99)=\frac{4.99}{(4.99+4)}

f(4.99)=0.55506117

At x=4.995:

we can plug x=4.995

f(4.995)=\frac{4.995}{(4.995+4)}

f(4.995)=0.55503085

At x=4.999:

we can plug x=4.999

f(4.999)=\frac{4.999}{(4.999+4)}

f(4.999)=0.55550616



7 0
4 years ago
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