Question

How to solve the indefinite integral

Answer 1

Answer:

$\frac{1}{4}x^4-x^2+3x+c$

Step-by-step explanation:

Use the the integration rules for powers of x: $\int x^n dx = \frac{1}{(n+1)} x^{n+1}$ and the additive property of integrals:

$f(x) = \int (x^3-2x+3)dx= \int x^3 dx-2\int x dx+\int 3 dx = \\=\frac{1}{4}x^4-x^2+3x+c$

with c being an arbitrary constant.