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IRISSAK [1]
3 years ago
15

The product of (3 + 2i) and a complex number is (17 + 7i)

Mathematics
1 answer:
Tatiana [17]3 years ago
8 0
<span> Of course you're looking for the ratio: (17+7i)/(3+2i). To get a clear number, you need to get a real number at the denominator -- and it so happens that the product of two complex conjugates is a real number. So, you multiply the denominator and the numerator by the conjugate of 3+2i. The denominator becomes 13 and the numerator becomes 51 + 7i. Hence, the multiplier is 51/13 + 7/13 i. </span>

<span>As a side note, while you probably knew how to factor a difference of squares, I just showed how to factor a sum of squares: a^2 + b^2 = (a + bi)(a - bi). That holds because i^2 = -1.

Hope this's useful/helpful !!!^_~!!!</span>
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The slope of the given line is the coefficient of x, 3/5. The slope of the perpendicular line will be the negative reciprocal of that: -1/(3/5) = -5/3.

The point-slope form of the equation for a line of slope m through point (h, k) can be written ...

... y = m(x -h) +k

For your point and the slope found above, this becomes

... y = (-5/3)(x -15) -5

When x=0, this is

... y = (-5/3)(-15) -5 = 20

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4 years ago
Which of the following is not the same as positive 7?
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3 years ago
Read 2 more answers
If x+1/x = 5 find the value of x^3 +1/x^3. pls solve​
Korolek [52]

Answer:

1) solve x+1/x = 5

\frac{x + 1}{x}  = 5

x + 1 = 5x

x - 5x =  - 1

- 4x =  - 1

x =  \frac{ -1}{ - 4}

x =  \frac{1}{4}

2) solve x³+1/x³

x {}^{3}  +  \frac{1}{x {}^{3} }

substitute x = 1/4 into the expression

( \frac{1}{4} ) {}^{3}  +  \frac{1}{( \frac{1}{4}) {}^{3}  }

\frac{1}{64}  +  \frac{1}{ \frac{1}{64} }

\frac{1}{64}  +  \frac{64 \times 1}{1}

\frac{1}{64}   + 64

\frac{4097}{64}  \: or \: 64.02

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Step-by-step explanation:

4 0
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