what is the y-intercept of the equation of the line that is perpendicular to the line y=3/5x+10 and passes through the point (15
,-5)
1 answer:
The slope of the given line is the coefficient of x, 3/5. The slope of the perpendicular line will be the negative reciprocal of that: -1/(3/5) = -5/3.
The point-slope form of the equation for a line of slope m through point (h, k) can be written ...
... y = m(x -h) +k
For your point and the slope found above, this becomes
... y = (-5/3)(x -15) -5
When x=0, this is
... y = (-5/3)(-15) -5 = 20
The y-intercept is 20.
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Answer:
AD = 7
Step-by-step explanation:
Given that the two triangles are similar by the SSS (side side side) postulate, the triangles share the same ratios when it comes to their sides.
We know the values for lines DB, EB and CB, therefore we can solve for AB, and subtract DB to find AD
We can solve the problem by solving for x:
Cross multiply.
Simplify.
Subtract the value of DB to find AD.