what is the y-intercept of the equation of the line that is perpendicular to the line y=3/5x+10 and passes through the point (15
,-5)
1 answer:
The slope of the given line is the coefficient of x, 3/5. The slope of the perpendicular line will be the negative reciprocal of that: -1/(3/5) = -5/3.
The point-slope form of the equation for a line of slope m through point (h, k) can be written ...
... y = m(x -h) +k
For your point and the slope found above, this becomes
... y = (-5/3)(x -15) -5
When x=0, this is
... y = (-5/3)(-15) -5 = 20
The y-intercept is 20.
You might be interested in
Answer:
a = 12m
Step-by-step explanation:
In order to solve this problem we will need to know the Pythagoras theorem that states that in a right angled triangle the square of the hypotenuse (the side opposite to the right angel) is equal to the sum of the squares of the other two sides. This theorem can be written as an equation....
Now we can see that we can easily find the missing value by using this theorem. We just have to substitute the values. And we get the following