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3 years ago

HELP How do I convert $0.31 into % Please show steps Thank you

2 answers:

6 0

I am a little confuse of the number that you have given because of the dollar sign. But perhaps, you might refer 0.31 only. If that is the case, you can convert 0.31 into percent by just moving two decimal places to the right, so it becomes 31%. Hope this answers your question.

Musya8 [376]3 years ago

3 0

In order to convert a number into a percentage, you need to divide that by 100
It would be: 0.31 = 0.31/100 = 0.0031

In short, Your Answer would be $0.0031%

Hope this helps!

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Westkost [7]

Answer:

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3 years ago

Please Help !!Mr. Mudd gives each of his children $2000 to invest as part of a friendly family competition. The competition will

VikaD [51]

Answer:

Albert = $2159.07; Marie = $2244.99; Hans = $2188.35; Max = $2147.40

Marie is $10 000 richer

Step-by-step explanation:

Albert

(a) $1000 at 1.2 % compounded monthly

$A = P\left(1 + \dfrac{r}{n}\right)^{nt}$

A = 1000(1 + 0.001)¹²⁰ = $1127.43

(b) $500 losing 2%

0.98 × 500 = $490

(c) $500 compounded continuously at 0.8%

$\begin{array}{rcl}A & = & Pe^{rt}\\& = & 500e^{0.008 \times 10}\\& = &\mathbf{\$541.64}\\\end{array}\\$

(d) Balance

Total = 1127.43 + 490.00+ 541.64 = $2159.07

Marie

(a) 1500 at 1.4 % compounded quarterly

A = 1500(1 + 0.0035)⁴⁰ = $1724.99

(b) $500 gaining 4 %

1.04 × 500 = $520.00

(c) Balance

Total = 1724.99 + 520.00 = $2244.99

Hans

$2000 compounded continuously at 0.9 %

$\begin{array}{rcl}A& = &2000e^{0.009 \times 10}\\& = &\mathbf{\$2188.35}\\\end{array}\\$

Max

(a) $1000 decreasing exponentially at 0.5 % annually

A = 1000(1 - 0.005)¹⁰= $951.11

(b) $1000 at 1.8 % compounded biannually

A = 1000(1 + 0.009)²⁰ = $1196.29

(c) Balance

Total = 951.11 + 1196.29 = $2147.40

Marie is $ 10 000 richer at the end of the competition.

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4 years ago

Express your answer as a polynomial in standard form

Bingel [31]

Answer:

f(g(x)) = 4x² + 16x + 13

Step-by-step explanation:

Given the composition of functions f(g(x)), for which f(x) = 4x + 5, and g(x) = x² + 4x + 2.

<h3>Definitions:</h3>

The polynomial in standard form has terms that are arranged by descending order of degree.

In the composition of function f with function g, which is alternatively expressed as f ° g, is defined as (f ° g)(x) = f(g(x)).

In evaluating composition of functions, the first step is to evaluate the inner function, g(x). Then, we must use the derived value from g(x) as an input into f(x).

<h3>Solution:</h3>

Since we are not provided with any input values to evaluate the given composition of functions, we can express the given functions as follows:

f(x) = 4x + 5

g(x) = x² + 4x + 2

f(g(x)) = 4(x² + 4x + 2) + 5

Next, distribute 4 into the parenthesis:

f(g(x)) = 4x² + 16x + 8 + 5

Combine constants:

f(g(x)) = 4x² + 16x + 13

Therefore, f(g(x)) as a polynomial in x that is written in standard form is: 4x² + 16x + 13.

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2 years ago