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3 years ago

How do you solve rational expressions

Mathematics

2 answers:

Stells [14]3 years ago

5 0

Answer:

lots of multiplying I've noticed

DedPeter [7]3 years ago

5 0

•Find the common denominator.

•Multiply everything by the common denominator.

•Simplify.

Check the answer(s) to make sure there isn't an extraneous solution.

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3x+3y=27 3x-3y= -11 using elimination

Taya2010 [7]

3x + 3y = 27
3x - 3y = -11
------------------add
6x = 16
x = 16/6 which reduces to 8/3

3x + 3y = 27
3(8/3) + 3y = 27
8 + 3y = 27
3y = 27 - 8
3y = 19
y = 19/3

solution is (8/3, 19/3)

3 0

3 years ago

The following polynomial is defined on the interval [-2, 2]:

Bess [88]

Answer:

Using Matlab code for Fourier series to calculate for the function, see the attached

Step-by-step explanation:

Go through the picture step by step.

6 0

4 years ago

What is the value of x in the equation X=-45? O-75 O -27 O 27 O 75

swat32

Answer:b

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

At what value of x do the graphs of the equations below intersect 2x-y=6 5x+10y=-10

Irina18 [472]

Answer:

The graphs of the equations intersect at x=2

Step-by-step explanation:

we have

$2x-y=6$ ----> equation A

$5x+10y=-10$ ----> equation B

Solve the system by graphing

Remember that the solution of the system of equations is the intersection point both lines

Using a graphing tool

The solution is the point (2,-2)

see the attached figure

therefore

The graphs of the equations intersect at x=2

5 0

3 years ago

Indiras spring garden has half as many tulips as daffodils and three times as many hyacinths as tulips. If there are a total of

kow [346]

Indira is having 34 tulips, 68 daffodils and 102 hyacinths , altogether 204 flowers in her spring garden.

Given, In Indira's springtime garden, there are three times more hyacinths than tulips and half as many daffodils as tulips.

let the number of tulips be = x

the number of daffodils be = y

the number of hyacinths be = z

hence according to the question,

tulips are (x) = 1/2 (y) = y/2

hyacinths are (z) = 3(x) = 3x

therefore, total flowers = 204

tulips ₊ daffodils ₊ hyacinths = 204

y/2 ₊ y ₊ 3x = 204

substitute x value in the above equation.

y/2 ₊ y ₊ 3(y/2) = 204

take LCM

y ₊ 2y ₊ 3y = 408

6y = 408

y = 408/6

y = 68

hence the number of daffodils is 68.

now substitute y value in x = y/2

x = 68/2

x = 34

now substitute x value in z= 3x

z = 3(34)

z = 102

hence we get the number of tulips,daffodils and hyacinths as 34 , 68 and 102 respectively.

Learn more about Solving equations here:

brainly.com/question/13729904

#SPJ9

6 0

1 year ago