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Talja [164]
3 years ago
9

What is a ratio called with two equivalent measurements?

Mathematics
1 answer:
AleksandrR [38]3 years ago
7 0
Ratio with two equivalent measurements would be 1
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Use the diagram to find the value of "x" so that △AOC ≅ △ZFD by HL.
astra-53 [7]

Answer:

x= 19

Step-by-step explanation:

Is given that the <u>triangles are congruent</u> so the corresponding sides are congruent as well.

Also congruent sides are equal in measure so we use the given picture to write the equality.

2x -1 = 37, add 1 to both sides

  2x = 38 , divide both sides by 2

    x = 19

8 0
2 years ago
Simplification of the expression (xyz2)4.
horrorfan [7]
(xyz²)⁴
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4 0
2 years ago
If tan x =8/15 and 0°&lt;x&lt;90°,find the value of cos x​
Shtirlitz [24]

9514 1404 393

Answer:

  15/17

Step-by-step explanation:

cos(arctan(8/15)) = 15/17

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You could assume the ratio values 8 and 15 represent the opposite and adjacent sides of a right triangle. Then the hypotenuse is ...

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The cosine is the ratio of the adjacent side to the hypotenuse, so is ...

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6 0
2 years ago
Can you please explain this to me and answer
ZanzabumX [31]
1)73 degrees
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23+84= 107
180-107=73

2) 28 degrees
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180-152= 28
5 0
2 years ago
Read 2 more answers
Please help me with #'s 5&amp;6
Fynjy0 [20]

5.\\(x+3)^2+7=-2\qquad|-7\\\\(x+3)^2=-9 < 0\\\\\text{NO REAL SOLUTION}\\\\(x+3)^2=-9\to x+3=\pm\sqrt{-9}\\\\x+3=-3i\ \vee\ x+3=3i\qquad|-3\\\\\boxed{x=-3-3i\ \vee\ x=-3+3i}

6.\\4(x-10)^2=25\qquad|:4\\\\(x-10)^2=\dfrac{25}{4}\to x-10=\pm\sqrt{\dfrac{25}{4}}\\\\x-10=-\dfrac{\sqrt{25}}{\sqrt4}\ \vee\ x-10=\dfrac{\sqrt{25}}{\sqrt4}\\\\x-10=-\dfrac{5}{2}\ \vee\ x-10=\dfrac{5}{2}\\\\x-10=-2.5\ \vee\ x-10=2.5\qquad|+10\\\\\boxed{x=7.5\ \vee\ x=12.5}

7 0
3 years ago
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