Answer:
580
Step-by-step explanation:
because you square the area and identify
The domain is the set of x-values of a function. The range is the set of y-values of a function.
You are told that the domain, or x-values, are -8, -6, -3, -2, and 2. To find the range, you just need to plug in each of the x-values into the function <span>y = -3x + 7 and find the value of y.
1) When x = -8:
</span><span>y = -3x + 7
y = -3(-8) + 7
y = 24 + 7
y = 31
2) When x = -6
</span>y = -3x + 7
y = -3(-6) + 7
y = 18 + 7
y = 25
3) When x = -3
y = -3x + 7
y = -3(-3) + 7
y = 9 + 7
y = 16
4) When x = -2
y = -3x + 7
y = -3(-2) + 7
y = 6 + 7
y = 13
5) When y = 2
y = -3x + 7
y = -3(2) + 7
y = -6 + 7
y = 1
The range is {31, 25, 16, 13, 1}.
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Answer: {31, 25, 16, 13, 1}
The answer should be 5 over 4
Answer:
-p5q2 - p3q5 + 2p3 + 2pq2 + 2q3
____________________________
p3q2
Step-by-step explanation:
2
Simplify ——
q2
Equation at the end of step 1 :
(p+q) 2
(((2•—————)-(q3))+——)-p2
(p3) q2
Step 2 :
p + q
Simplify —————
p3 (p + q) 2
(((2 • ———————) - q3) + ——) - p2
p3 q2
Step 3 : 2 • (p + q) 2
((——————————— - q3) + ——) - p2
p3 q2 q3 q3 • p3
q3 = —— = ———————
1 p3
The square root of 8 added to the square root of 18 equals 7.07106781187
