The present age of mother and her daughter respectively are; 40 and 10 years respectively.
<h3>How to Solve Algebra Word Problems?</h3>
Let x and y be the present age of mother and her daughter respectively.
Therefore;
x + y = 50
x = 50 − y .....(1)
After 20 years, mother's age will be twice her daughter's age at the time. Thus;
x + 20 = 2(y + 20)
x − 2y = 20 .....(2)
Plugging eq 1 into eq 2 gives us;
50 − y − 2y = 20
3y = 30
y = 10
Thus;
x = 50 − 10
x = 40
Thus, the present age of mother and her daughter is 40 and 10 years respectively.
Translation of the question into English is;
The sum of the present ages of mother and her daughter is 50 years. After 20 years, mother's age will be twice her daughter's age at the time. Find their present ages.
Read more about Algebra Word Problems at; brainly.com/question/21405634
#SPJ1
Answer:
Step-by-step explanation:
Answer:
Add
Step-by-step explanation:
10.65*40=426
426+50=476
Answer:
33
Step-by-step explanation:
So I just put them in order....18,19,23,25,28,30,31,33,33,35,36
and you can see that 33 pops up twice when the others only pop up once..so the answer is 33
Answer: I got D i'm not sure if that right though..
Step-by-step explanation:
